Reputation: 11
I got fiddler to capture a GET request, I want to re send the exact request with python. This is the request I captured:
GET https://example.com/api/content/v1/products/search?page=20&page_size=25&q=&type=image HTTP/1.1
Host: example.com
Connection: keep-alive
Search-Version: v3
Accept: application/json
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36
Referer: https://example.com/search/?q=&type=image&page=20
Accept-Encoding: gzip, deflate, br
Accept-Language: en-US,en;q=0.9
Upvotes: 1
Views: 20865
Reputation: 159
You can use the requests module.
The requests
module automatically supplies most of the headers for you so you most likely do not need to manually include all of them.
Since you are sending a GET request, you can use the params
parameter to neatly form the query string.
Example:
import requests
BASE_URL = "https://example.com/api/content/v1/products/search"
headers = {
"Connection": "keep-alive",
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36"
}
params = {
"page": 20,
"page_size": 25,
"type": "image"
}
response = requests.get(BASE_URL, headers=headers, params=params)
Upvotes: 8
Reputation: 1480
import requests
headers = {
'authority': 'stackoverflow.com',
'cache-control': 'max-age=0',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36',
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'referer': 'https://stackoverflow.com/questions/tagged/python?sort=newest&page=2&pagesize=15',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.9,tr-TR;q=0.8,tr;q=0.7',
'cookie': 'prov=6bb44cc9-dfe4-1b95-a65d-5250b3b4c9fb; _ga=GA1.2.1363624981.1550767314; __qca=P0-1074700243-1550767314392; notice-ctt=4%3B1550784035760; _gid=GA1.2.1415061800.1552935051; acct=t=4CnQ70qSwPMzOe6jigQlAR28TSW%2fMxzx&s=32zlYt1%2b3TBwWVaCHxH%2bl5aDhLjmq4Xr',
}
response = requests.get('https://stackoverflow.com/questions/55239787/how-to-send-a-get-request-with-headers-via-python', headers=headers)
This is an example of how to send a get request to this page with headers.
Upvotes: 1
Reputation: 13890
You may open SSL socket (https://docs.python.org/3/library/ssl.html) to example.com:443
, write your captured request into this socket as raw bytes, and then read HTTP response from the socket.
You may also try to use http.client.HTTPResponse
class to read and parse HTTP response from your socket, but this class is not supposed to be instantiated directly, so some unexpected obstacles could emerge.
Upvotes: 0