CODEWITHSUNDEEP
hiveqlbeelinehivecli
BlackMamba
BlackMamba

Reputation: 10252

How to use hive variable substitution rightly

When I'm using variable substitution in hive, I meet some errors, but I need your help.

My code:

set hievar:b='on t1.id=t2.id where t2.id is null';
select * from t_old as t1 full outer join t_new as t2 ${b};

when I run this code in hive shell, it give me some error about ${b}.

I also try this:

set hivevar:c='select * from t_old as t1 full outer join t_new as t2 on t1.id=t2.id where t2.id is null';
${c};

It gives me the same error.

Upvotes: 1

Views: 359

Answers (1)

leftjoin
leftjoin

Reputation: 38335

Fix hivevar namespace name (in your code it is hievar) and remove quotes, because they are also passed as is in Hive.

Example:

set hivevar:b=where 1=1; --without quotes
select 1 ${hivevar:b}; --you can do without hivevar: as in your example

Result:

OK
1
Time taken: 0.129 seconds, Fetched: 1 row(s)

Second example:

hive> set hivevar:c=select 1 where 1=1;
hive> ${c};
OK
1
Time taken: 0.491 seconds, Fetched: 1 row(s)

Upvotes: 0

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