Reputation: 1972
I have a list of urls:
images=['https://example.co/123','https://example.co/124',...]
I need to create another list like so:
files=[('images',requests.get(image).content),('images',requests.get(image).content),..]
I need a list of ('images',requests.get(image).content)
for each image url in images list. How can this be done?
Upvotes: 0
Views: 16
Reputation: 54162
Sounds like a job for list comprehensions.
images=['https://example.co/123','https://example.co/124', ...]
files = [('images', requests.get(image).content) for image in images]
Upvotes: 1