CODEWITHSUNDEEP
pythonpython-3.xsocketsservernetwork-programming
Ethan
Ethan

Reputation: 321

sending file through socket in python 3

In the code below I've tried to send an image using the python socket module in one machine to another machine. So I have 2 files: client.py and Server.py

as I figured it out the problem is when I read the image(as bytes) at the client machine and then the server tries to receive the file, at that moment when sending process is done before the receiving process then the error below occurs at line 13 of the client code:

BrokenPipeError: [Errno 32] Broken pipe

I want to find out what this error is and why does it occur in my code.

Server.py

import socket

host = '192.168.1.35'
port = 5000

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host,port))
s.listen(1)

while True:
    conn , addr = s.accept()
    data = conn.recv(1024)

    with open(r"C:\Users\master\Desktop\music.jpg",'wb') as f:
        f.write(data)
        # conn.send(b'done')
        data = conn.recv(1024)
        if not data:
            break
            conn.send(b'done')
    conn.send(b'done')
    conn.close()
s.close()

Client.py

import socket

def main():

    HOST = '192.168.1.35'  
    PORT = 5000

    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    s.connect((HOST, PORT))
    f = open('/home/taha/Desktop/f.jpg','rb')
    data = f.read()
    s.sendfile(f)
    if s.recv(1024) == b'done':
        f.close()

    s.close()

if __name__ == '__main__':
    main()

Upvotes: 0

Views: 1827

Answers (1)

Lior Cohen
Lior Cohen

Reputation: 5755

You are closing the server connection before the client read the “done”

Upvotes: 2

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