CODEWITHSUNDEEP
pythondjangopython-3.xwebsocketdjango-channels
Mukul Mantosh
Mukul Mantosh

Reputation: 368

sending notification to one user using Channels 2

I want to send notification to specific authenticated user using Channels 2.

In below code i am sending notification as a broadcast instead of that i want to send notification to a specific user.

from channels.generic.websocket import AsyncJsonWebsocketConsumer


class NotifyConsumer(AsyncJsonWebsocketConsumer):

    async def connect(self):
        await self.accept()
        await self.channel_layer.group_add("gossip", self.channel_name)
        print(f"Added {self.channel_name} channel to gossip")

    async def disconnect(self, close_code):
        await self.channel_layer.group_discard("gossip", self.channel_name)
        print(f"Removed {self.channel_name} channel to gossip")

    async def user_gossip(self, event):
        await self.send_json(event)
        print(f"Got message {event} at {self.channel_name}")

Upvotes: 3

Views: 2441

Answers (1)

Sreekanth Reddy Balne
Sreekanth Reddy Balne

Reputation: 3424

Most users new to Django-channels 2.x face this problem. let me explain.

self.channel_layer.group_add("gossip", self.channel_name) takes two arguments: room_name and channel_name

When you connect from your browser via socket to this consumer, you are creating a new socket connection called as channel. So, when you open multiple pages in your browser, multiple channels are created. Each channel has a unique Id/name : channel_name

room is a group of channels. If anyone sends a message to the room, all channels in that room will receive that message.

So, if you need to send a notification/message to a single user, then you must create a room only for that particular user.

Assuming that current user is passed in the consumer's scope.

self.user = self.scope["user"]
self.user_room_name = "notif_room_for_user_"+str(self.user.id) ##Notification room name
await self.channel_layer.group_add(
       self.user_room_name,
       self.channel_name
    )

Whenever you send/broadcast a message to user_room_name, It will only be received by that user.

Upvotes: 18

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