Reputation: 39
I've been trying to sum a certain digit from a number, for example
Number: 5
Input: 54365
Output: The sum of 5's is 10
Second example:
Number: 5
Input: 5437555
Output: The sum of 5's is 20
I've managed to separate the digits yet I couldn't find the condition to sum
a certain number (for instance number 5
like the examples).
I'd appreciate to hear your idea of doing it
public static void main(String[] args) {
int sum = 0;
int number = MyConsole.readInt("Enter a number:");
while (number > 0) {
if (number % 10 == 8) {
sum += 8;
} else {
number /= 10;
}
}
System.out.println("The sum of 8's is:" + sum);
}
My way of separating the numbers.
Also i have a small program to get input instead of using scanner since we still haven't went through it in class.
Upvotes: 0
Views: 92
Reputation: 21172
Your requirement seems reasonably clear to me. Given a number
final int number = 5;
And a starting number
final int input = 54365;
The easiest way is to convert that number to a String
final int inputStr = String.valueOf(input);
Then, you can filter
each char for it, and sum
them
final int sum =
inputStr.chars() // Get a Stream of ints, which represent the characters
.map(Character::getNumericValue) // Convert a char to its numeric representation
.filter(i -> i == number) // Filter for the designated number
.sum(); // Sum all the filtered integers
Output: 10
Using the same approach, but with an old-style for
loop
final int input = 54365;
final int inputStr = String.valueOf(input);
final int number = 5;
int sum = 0;
for (final char c : inputStr.toCharArray()) {
final int n = Character.getNumericValue(c);
if (n == number) {
sum += number;
}
}
Your solution can work
int number = 5;
int input = 543655;
int sum = 0;
while (input > 0) {
if (input % 10 == number) {
sum += number;
}
input /= 10;
}
Upvotes: 1