Reputation: 1667
Nested dictionaries in Python
Scenario: From my previous question (Organizing pythonic dictionaries for a JSON schema validation), I am now trying to create my dictionaries in a more efficient manner. Instead of feeding all the information at once to the dictionary, I am trying to pass it step by step.
What I have so far:
cldr["holidays"] = {"type": "object",
"description": "Holiday specification",
"properties": {
"default":{
"type": "object",
"description": "Calendars used",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
},
"exante": {
"type": "object",
"description": "Calendars used",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
},
"expost": {
"type": "object",
"description": "Calendars used",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
},
}
}
What I am trying to do:
cldr["holidays"] = {"type": "object",
"description": "Holiday specification",
"properties": {"default", "exante", "expost"}
}
cldr["holidays"]["properties"]["default"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["exante"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["expost"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
But that yields the following error:
TypeError: 'set' object does not support item assignment
Question1: Any ideas on what I am doing wrong?
Question2: Would it be possible to create a shared class for the inner parts of this dictionaries? Since they would be inherently the same, do I need to define each of them separately or is there a way to do it more efficiently?
Upvotes: 0
Views: 68
Answers (1)
Reputation: 1334
What's wrong about this?
You're mistakenly creating a set at the properties key.
cldr["holidays"] = {"type": "object",
"description": "Holiday specification",
"properties": {"default", "exante", "expost"} # creates a set
}
cldr["holidays"]["properties"]["default"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["exante"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["expost"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
Here's how you correct that
Give the properties key a value that's an empty dictionary. When you do cldr["holidays"]["properties"]["default"] = {the inner dictionary}, you'll be setting the default key and its value..
cldr["holidays"] = {"type": "object",
"description": "Holiday specification",
"properties": {} # creates an empty dictionary
}
cldr["holidays"]["properties"]["default"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["exante"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"]["properties"]["expost"] = {
"type": "object",
"description": "",
"properties":{
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
What it sounds like you want
def holiday_property():
return {
"type": "object",
"description": "",
"properties": {
"ref": {"type": "string"},
"type": {"type": "string"},
"value": {"type": "string"}
}
}
cldr["holidays"] = {
"type": "object",
"description": "Holiday specification",
"properties": {}
}
cldr["holidays"]["properties"]["default"] = holiday_property()
cldr["holidays"]["properties"]["exante"] = holiday_property()
cldr["holidays"]["properties"]["expost"] = holiday_property()
Upvotes: 1