CODEWITHSUNDEEP
vbaweb-scrapingxmlhttprequest
quicksilv86
quicksilv86

Reputation: 105

XMLHTTP with Hash character



I'm trying to scrape a website with xmlhttp and VBA.

The Url has a hash(#) symbol and is misinterpreted by VBA...

This is the same problem as explained here : Error in XMLHTTP Get request with Special character in URL
The code is as follow : 

Sub webscraping()
Dim x               As String
Dim req             As MSXML2.XMLHTTP60
Dim doc             As HTMLDocument

x = "https://search.gleif.org/#/search/"

Set req = New MSXML2.XMLHTTP60
    With req
        .Open "GET", x, False
        .send
        If .Status <> 200 Then
            MsgBox "Http Request Error"
            Exit Sub
        End If
        Set doc = New MSHTML.HTMLDocument
        doc.body.innerHTML = .responseText
    End With
End Sub

Thank you in advance

Upvotes: 3

Views: 367

Answers (1)

QHarr
QHarr

Reputation: 84465

You can side step this by calling the API direct with your search term as shown below. I am using a json parser to handle the json response. After adding the .bas at the link to your project, also go VBE > Tools > References > Add a reference to Microsoft Scripting Runtime.

Note there are queryString parameters you can alter here: "&page%5Bnumber%5D=1&page%5Bsize%5D=15". This is currently with page=1 and records per page at 15.

VBA:

Option Explicit
Public Sub webscraping()
    Dim url As String
    Dim req As MSXML2.XMLHTTP60
    Dim doc As HTMLDocument
    Dim json As Object
    Const TERM = "banana corp."

    url = "https://api.gleif.org/api/v1/lei-records?filter%5Bfulltext%5D=" & Application.EncodeURL(TERM) & "&page%5Bnumber%5D=1&page%5Bsize%5D=15"

    Set req = New MSXML2.XMLHTTP60
    With req
        .Open "GET", url, False
        .send
        If .Status <> 200 Then
            MsgBox "Http Request Error"
            Exit Sub
        End If
        Set json = JsonConverter.ParseJson(.responseText)
    End With
    Stop
    'Do something with json
End Sub

There is a lot of info returned so here is just an extract from it:

Research the API here:

https://www.gleif.org/en/lei-data/gleif-lei-look-up-api/access-the-api

Upvotes: 1

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