CODEWITHSUNDEEP
bashloopsscope
Noob
Noob

Reputation: 11

How to make local variable pass from one loop to another

Trying to pull an entry from two files (foofile, barfile) and pass them into a third file (dothis.sh) as arguments. It works for bar but not for foo since this looks be a scope related issue. I tried to nest the foo loop into the bar loop too with no success:

    #!/bin/bash
    while read foo
                do
                        #echo $foo
                        export foo
    done < FooFile

    while read bar
        do
                #echo $bar
                export bar
    ./dothis.sh $bar $foo
    done < BarFile

Upvotes: 1

Views: 239

Answers (2)

jhnc
jhnc

Reputation: 16662

Here's a way to loop with two inputs at the same time in bash:

#!/bin/bash

while read -u 100 foo && read -u 101 bar; do
    ./dothis.sh "$foo" "$bar"
done 100<FooFile 101<BarFile

It will terminate when one file has no more lines to read.

Upvotes: 2

Mark
Mark

Reputation: 4455

foo is in scope in your program, but it is empty.
Consider this code:

foo="test"
while read foo; do echo $foo; done < /dev/null
echo "foo=$foo"

The result is:

foo=

The problem is that foo will be set to empty when read has no input. That's what's happening in your program.

That said, pay attention to oguzismail's comment. (S)he is leading you a good direction:

paste FooFile BarFile | xargs -n 2 ./dothis.sh

It's really an excellent start and probably all you'll need in the simple cases where FooFile and BarFile have the same amount of entries.

Upvotes: 1

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