CODEWITHSUNDEEP
scalamathfitness
Edgar Ustian
Edgar Ustian

Reputation: 1

How to clamp a value from 0 to infinite to a value from 1 to 0?

I am creating a program in Scala that needs to generate a fitness function based on the line that I provide it with.

To generate the fitness function I wrote a method that takes a list of points and returns a fitness function based on those points.

This fitness function should measure the sum of the distances of each point from the line in terms of their y values. And the lower the sum the higher the fitness.

But now I am stuck, because I can't figure out how I can transform the sum of the distances from 0 to Infinite to a Double which is from 1 to 0, 1 the best fit and 0 being the worst fit line.

Any ideas or maths equation ? Thank you in advance

I have already tried to clamp this value using the tanh function only to realize that it works horribly for larger values. I have also tried doing it using:

fitness = 1 - Math.atan(x)/(Math.PI/2);

So that I could maybe get the reverse answer, but it didn't work :'^)

This is the code that pertains to how my program runs:

//Point Class that is just a coordinate point (x, y)
class Point(val x: Double, val y: Double) {
}

//Line Class this is just a line with y = slope * x + yIntercept
class Line(val slope: Double, val yIntercept: Double) {

  def evaluate(x: Double): Double = {
    slope * x + yIntercept
  }
}

def lineFitFuncGen(points: List[Point]): Line => Double = {
    //Sum of the distances using the line given
    line: Line => {
      var lineSum: Double = 0.0
      for (point <- points) {
        lineSum += Math.abs(line.evaluate(point.x) - point.y)
      }
      lineSum
    }
  }

I run the program and I get the sum but now I don't know how to take this sum and convert it into a range of 1 to 0. And I want to make it so that my lowest sum possible, which is 0 gives me fitness of 1, while my highest sum possible, which is Infinity gives me fitness of 0

Upvotes: 0

Views: 578

Answers (2)

Alan
Alan

Reputation: 976

How about

fitness = 1/(1+x);

a function that goes towards 0 as x increases

Upvotes: 2

Amadan
Amadan

Reputation: 198314

Maths, not programming. But...

fitness(x) = 2 / (exp(x) + 1)

is sigmoid function adapted for your requirements (fitness(0) = 1, fitness(inf) = 0).

Upvotes: 2

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