CODEWITHSUNDEEP
javagenericsarraylist
user9608350
user9608350

Reputation:

How is it possible to add a double into an ArrayList of Integer? (Java)

I try to understand how is it possible to have a Double value into an ArrayList of Integer. The numList is an ArrayList of Integer, and the value from it is a Double.

This is the code:

package bounded.wildcards;

import java.util.ArrayList;
import java.util.List;

public class GenericsDemo {

    public static void main(String[] args) {
        // Invariance Workaround
        List<Integer> numList = new ArrayList<>();
        GenericsDemo.invarianceWorkaround(numList);
        System.out.println(numList);
    }

    static <T extends Number> void invarianceWorkaround(List<T> list) {

        T element = (T) new Double(23.3);  
        list.add(element);
    }

}

This will compile and run without an error.

Upvotes: 15

Views: 3078

Answers (1)

Jiri Tousek
Jiri Tousek

Reputation: 12440

This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer> into List<Object>.

My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.

Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println() is not such operation.

If you change the print code to

Integer num = numList.get(0);
System.out.println(num);

this will now involve runtime type check and will therefore fail:

java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer

Upvotes: 21

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