CODEWITHSUNDEEP
swiftstoryboardscreen-size
suxrule
suxrule

Reputation: 65

Using different storyboards for different screen sizes on load? xcode Swift

I just want to load a specific storyboard when a certain iPhone size loads the app. I'm really struggling to get the desired out come using auto layout.

I've done a lot of searching and found code someone shared 4 years ago and tried using it but I got a lot of errors, could someone with more knowledge have a look at the code and see if it needs updating please?

    func application(application: UIApplication, 
    didFinishLaunchingWithOptions launchOptions: [NSObject: 
    AnyObject]?) -> Bool {

var bounds: CGRect = UIScreen.mainScreen().bounds
var screenHeight: NSNumber = bounds.size.height
var deviceFamily: String

var mainView: UIStoryboard!
mainView = UIStoryboard(name: "iphone35Storyboard", bundle: nil)
let viewcontroller : UIViewController = mainView.instantiateViewControllerWithIdentifier("iphone35") as UIViewController
self.window!.rootViewController = viewcontroller

if screenHeight == 480  {
    deviceFamily = "iPhoneOriginal"
    // Load Storyboard with name: iPhone4
    var mainView: UIStoryboard!
    mainView = UIStoryboard(name: "Main", bundle: nil)
    let viewcontroller : UIViewController = mainView.instantiateViewControllerWithIdentifier("iphone4") as UIViewController
    self.window!.rootViewController = viewcontroller

} else {

    var mainView: UIStoryboard!
    mainView = UIStoryboard(name: "IpadStoryboard", bundle: nil)
    let viewcontroller : UIViewController = mainView.instantiateViewControllerWithIdentifier("ipad") as UIViewController
    self.window!.rootViewController = viewcontroller

    if screenHeight == 920 {
        deviceFamily = "Pad"
        // Load Storyboard with name: ipad
        var mainView: UIStoryboard!
        mainView = UIStoryboard(name: "IpadStoryboard", bundle: nil)
        let viewcontroller : UIViewController = mainView.instantiateViewControllerWithIdentifier("ipad") as UIViewController
        self.window!.rootViewController = viewcontroller
    }
    }
    }

Errors experienced -

Instance method 'application(application:didFinishLaunchingWithOptions:)' nearly matches optional requirement 'application(_:didFinishLaunchingWithOptions:)' of protocol 'UIApplicationDelegate'

'instantiateViewControllerWithIdentifier' has been renamed to 'instantiateViewController(withIdentifier:)'

Cannot call value of non-function type 'UIScreen'

Cannot convert value of type 'CGFloat' to specified type 'NSNumber'

Upvotes: 1

Views: 706

Answers (1)

Vincent Joy
Vincent Joy

Reputation: 2678

Swift is still evolving and with every version of Swift there are many changes in the syntax. All those errors that you are getting are because that 4 years old code was meant for some older versions of swift. In Swift 4, you can use 

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {

        self.window = UIWindow(frame: UIScreen.main.bounds)

        let deviceIdiom = UIScreen.main.traitCollection.userInterfaceIdiom

        if deviceIdiom == .pad {

            let storyboard = UIStoryboard(name: "YourFirstStoryboard", bundle: nil)
            if let firstVC = storyboard.instantiateViewController(withIdentifier: "FirstVC_Identifier") as? FirstVC {
                self.window?.rootViewController = firstVC
            }

        } else if deviceIdiom == .phone {

            if (UIDevice.current.userInterfaceIdiom == .phone) && (UIScreen.main.bounds.size.height < 568.0) {

                /* "< 568" = iphone 4 or less */
                /* Similarly you can use other "else if" conditions with.. */
                /* "== 568" = iphone 5 and 5c */
                /* "== 667" = iphone 6,7 or 8 */
                /* "== 736" = iphone 6P,7P or 8 */
                /* "== 812" = iphone X, XR or XS */
                /* "== 896" = iphone X, XR or XS */

                let storyboard = UIStoryboard(name: "YourSecondStoryboard", bundle: nil)
                if let secondVC = storyboard.instantiateViewController(withIdentifier: "SecondVC_Identifier") as? SecondVC {
                    self.window?.rootViewController = secondVC
                }

            }
        }

        self.window?.makeKeyAndVisible()

        return true
    }

Upvotes: 3

Related Questions