Reputation: 23295
Is there a module for perl that will parse this format of date into a DateTime
object?
Thursday, September 13, 2007
I have tried DateTime::Format::Natural
but it doesn't seem to work.
I would prefer a function that doesn't mind if there isn't a day of the week, for instance. I can't be sure if the data will be consistent.
Upvotes: 0
Views: 127
Reputation: 386706
This can be achieved using DateTime::Format::Flexible.
use DateTime::Format::Flexible qw( );
my $dt = DateTime::Format::Flexible->parse_datetime(
'Thursday, September 13, 2007',
lang => [ 'en' ], # Optional
);
If you had known the specific format (as in your original question), I would have recommended DateTime::Format::Strptime.
use DateTime::Format::Strptime qw( );
my $format = DateTime::Format::Strptime->new(
pattern => '%A, %B %e, %Y',
locale => 'en',
on_error => 'croak',
);
my $dt = $format->parse_datetime('Thursday, September 13, 2007');
Upvotes: 3