CODEWITHSUNDEEP
regexgo
Anh Vinh Huỳnh
Anh Vinh Huỳnh

Reputation: 331

Regex find many word in the string

I want to get all work in string - that are between the pair of {word}

Example: 

payment://pay?id={appid}&transtoken={transtoken}

Result expect: 

["appid", "transtoken"]

With regex partern: {\w+}, I only can get [{appid}, {transtoken}].

Please help me with the problem.

Upvotes: 2

Views: 1019

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626748

You may use the following pattern with FindAllStringSubmatch:

{(\w+)}

See the Go regexp documentation:

FindAllStringSubmatch is the 'All' version of FindStringSubmatch; it returns a slice of all successive matches of the expression, as defined by the 'All' description in the package comment. A return value of nil indicates no match.

and

FindStringSubmatch returns a slice of strings holding the text of the leftmost match of the regular expression in s and the matches, if any, of its subexpressions, as defined by the 'Submatch' description in the package comment. A return value of nil indicates no match.

See the Go demo:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    s := `payment://pay?id={appid}&transtoken={transtoken}`
    rex := regexp.MustCompile(`{(\w+)}`)
    results := rex.FindAllStringSubmatch(s,-1)
    for _, value := range results  {
        fmt.Printf("%q\n", value[1])
    }
}

Output:

"appid"
"transtoken"

Upvotes: 4

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