Reputation: 149
I am trying to export characters from a reference file in which their byte position is known. To do this, I have a long list of numbers stored as a variable which have been used as the input to a tail command.
For example, the reference file looks like:
ggaaatgcattcaaacatgc
And the list looks like:
5
10
7
15
I have tried using this code:
list=$(<pos.txt)
echo "$list"
cat ref.txt | tail -c +"list" | head -c1 > out.txt
However, it keeps returning "invalid number of bytes: '+5\n10\n7\n15...'"
My expected output would be
a
t
g
a
...
Can anybody tell me what I'm doing wrong? Thanks!
Upvotes: 2
Views: 1925
Reputation: 50815
You could use cut
instead of tail
:
pos=$(<pos.txt)
cut -c ${pos//$'\n'/,} --output-delimiter=$'\n' ref.txt
Or just awk:
awk -F '' 'NR==FNR{c[$0];next} {for(i in c) print $i}' pos.txt ref.txt
both yield:
a
g
t
a
Upvotes: 1
Reputation: 85895
The reason for your command failure is simple. The variable list
contains a multi-line string stored from the pos.txt
files including newlines. You cannot pass not more than one integer value for the -c
flag.
Your attempts can be fixed quite easily with removing calls to cat
and using a temporary variable to hold the file content
while IFS= read -r lineNo; do
tail -c "$lineNo" ref.txt | head -c1
done < pos.txt
But then if your intentions is print the desired output in a new-line every time, head
does not output that way. It just forms a string atga
for your given input in a single line and not across multiple lines with one character at each line.
As Gordon mentions in one of the comments, for much more efficient FASTA files processing, you could just use one invocation of awk
though (skipping multiple forks to head
/tail
). Your provided input does not involve any headers to skip which would be straightforward as
awk ' FNR==NR{ n = split($0,arr,""); for(i=1;i<=n;i++) hash[i] = arr[i] }
( $0 in hash ){ print hash[$0] } ' ref.txt pos.txt
Upvotes: 2
Reputation: 307
It looks like you are trying to access your list
variable in your tail command. You can access it like this: $list
rather than just using quotes around it.
Your logic is flawed even after fixing the variable access. The list
variable includes all lines of your list.txt
file. Including the newline character \n
which is invisible in many UIs and programs, but it is of course visible when you are manually reading single bytes. You need to feed the lines one by one to make it work properly.
Also unless those numbers are indexes from the end, you need to feed them to head instead of tail.
If I understood what you are attempting to do correctly, this should work:
while read line
do
head -c $line ref.txt | tail -c 1 >> out.txt
done < pos.txt
Upvotes: 3