CODEWITHSUNDEEP
javaoopmathinterfacepackage
Twisted Fate
Twisted Fate

Reputation: 145

Java interface with classes for volume and area of shapes

I'm a very green thumb to Java and would like to know how to properly use an interface to connect classes.

Say there is an interface X, in package Y for the volume and area of a shape

package Y;

public interface Shape {
    public double volume();

    public double surfaceArea();
}

Given a class called tetrahedron, where the math for the volume and area are respectively 

package Y;

public class Tetrahedron implements Shape{
    Tetrahedron(double edge) {
        (volume) Math.pow(edge, 3)/(6*Math.sqrt(2));
        (area) Math.sqrt(3)*Math.pow(edge, 2);
    }
}

Which is then once again accessed by the main class, also in package Y

package Y;

public class Main {
    static void main(String[] args){
        Shape a = new Tetrahedron(5);
        System.out.println(a.volume());
        System.out.println(a.surfaceArea());
    }
}

How exactly would you go about connecting the interface to the second class? As far as I am aware, you cannot simply override the value of volume and surfaceArea by doing something such as volume = x, so how exactly does one use the interface to get from A to B to C?

Upvotes: 0

Views: 1777

Answers (1)

vijay
vijay

Reputation: 187

I think you should do like this.

public interface Shape {
    public double volume();

    public double surfaceArea();
}

public class Tetrahedron implements Shape{
    double edge;
    Tetrahedron(double edge) {
        this.edge=edge;
    }

    @Override
    public double volume(){
         return Math.pow(edge, 3)/(6*Math.sqrt(2));
    }

    @Override
    public double surfaceArea(){
         return Math.sqrt(3)*Math.pow(edge, 2);
    }
}

Upvotes: 1

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