CODEWITHSUNDEEP
python
kingkongman oftheworldinchaos
kingkongman oftheworldinchaos

Reputation: 151

Print linkedlist nodes

I would like to first create my linkedlist and then print the list list nodes. I tried a few methods but always getting a wrong output.

Below is my code:

class node:
    def __init__(self, dataVal=None):
        self.dataVal = dataVal
        self.nextVal = None

class LinkedList:
    def __init__(self):
        self.headVal = None

    def printList(self):
        printVal = self.headVal
        while printVal is not None:
            print(printVal.dataVal)
            printVal = printVal.nextVal

    def insertEnd(self, n_node):
        new_node = node(n_node)
        if self.headVal is None:
            self.headVal = node(new_node)
        else:
            end = self.headVal
            while(end.nextVal):
                end = end.nextVal
            end.nextVal = new_node

def createList(array, n):
    linkedList = LinkedList()
    for i in range(n):
        linkedList.insertEnd(array[i])
    return linkedList

if __name__=='__main__':
    t = 2
    n = [5,6]
    array = [[1,2,3,4,5], [2,3,6,7,5,1]]
    for i in range(t):        
        head = createList(array[i], n[i])
        print(head.printList())

My current output:

<__main__.node object at 0x0000026152300400>
2
3
4
5
None
<__main__.node object at 0x00000261523257B8>
3
6
7
5
1
None

My expected should be:

<__main__.node object at 0x0000026152300400>
1
2
3
4
5

<__main__.node object at 0x00000261523257B8>
2
3
6
7
5
1

I do not know why the "None" appears and also why the object printed as well. Can anyone help?

Upvotes: 1

Views: 70

Answers (1)

nathancy
nathancy

Reputation: 46710

Remove the print to get rid of None. Change 

print(head.printList())

to

head.printList()

Also 

if self.headVal is None:

is equivalent to but more pythonic

if not self.headVal:

Upvotes: 1

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