CODEWITHSUNDEEP
chexstrtoul
user366312
user366312

Reputation: 16988

What does the 2nd argument in strtoul() function do?

According to this document,

The second argument (char **endptr) seems to be a waste of space! If it is set to NULL, STRTOL seems to work its way down the string until it finds an invalid character and then stops. All valid chars read are then converted if the string starts with an invalid character the function returns ZERO (0).

It means that the following code should detect 2 as the hex number:

int main()
{
    char * string = "p1pp2ppp";

    unsigned integer = strtoul(string, NULL, 16);

    printf("%u", integer);

    return 0;
}

but, it is returning zero.

Why?

Upvotes: -1

Views: 1210

Answers (3)

John Bode
John Bode

Reputation: 123538

The char **endptr argument in all the strto* functions is intended to receive the address of the first character that isn’t part of a valid integer (decimal, hex, or octal) or floating point number. Far from useless, it’s handy for checking invalid input. For example, if I meant to type in 1234 but fat-fingered something like 12w4, strtoul will return 12 and set the endptr argument to point to w.

Basically, if the character endptr points to isn’t whitespace or 0, then the input should most likely be rejected.

Upvotes: 0

dbush
dbush

Reputation: 224352

The man page says the following about the second argument:

If endptr is not NULL, strtol() stores the address of the first invalid character in *endptr. If there were no digits at all, strtol() stores the original value of nptr in *endptr (and returns 0). In particular, if *nptr is not '\0' but **endptr is '\0' on return, the entire string is valid.

For example:

char str[] = "123xyz45";
char *p;
long x = strtol(str, &p, 10);
printf("x=%ld\n", x);
printf("p - str = %d\n", p - str);
printf("*p = %c\n", *p);
printf("p (as string) = %s\n", p);

Output:

x=123
p - str = 3
*p = x
p (as string) = xyz45

We can see that when strtol returns p points to the first character in str that cannot be converted. This can be used to parse through the string a bit at a time, or to see if the entire string can be converted or if there are some extra characters.

In the case of your example, the first character in string, namely "p" is not a base 10 digit so nothing gets converted and the function returns 0.

Upvotes: 1

pmg
pmg

Reputation: 108978

Why?

It's returning 0 because "p..." does not follow any rules about integer representation. The 2nd argument is not relevant for your question.

Upvotes: 0

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