KM6895
KM6895

Reputation: 89

How to sequence a number in XSLT 2.0?

I have following input XML

<?xml version="1.0" encoding="UTF-8"?>
<Workers>
<Worker>
    <id>1234</id>
    <loc>New York</loc>
    <Days>1</Days>
    <StartDate>2019-01-26</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <Batch>A</Batch>
    <Days>3</Days>
    <Units>2</Units>
    <StartDate>2019-02-01</StartDate>
</Worker>
</Workers>

My code looks like below

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result- 
prefixes="#all">
<xsl:output method="xml" omit-xml-declaration="no" indent="yes"/>
<xsl:strip-space elements="*"/>

 <xsl:template match="Worker[Batch]">
 <xsl:variable name="currElem" select="."/>
 <xsl:for-each select="1 to Days">
  <xsl:apply-templates select="$currElem" mode="replicate">
    <xsl:with-param name="dayNo" select="."/>
  </xsl:apply-templates>
</xsl:for-each>
<xsl:for-each select="1 to Units">
  <xsl:apply-templates select="$currElem" mode="replicate">
    <xsl:with-param name="dayNo" select="."/>
  </xsl:apply-templates>
</xsl:for-each>
</xsl:template>

<xsl:template match="Worker" mode="replicate">
<xsl:param name="dayNo"/>
<Worker>
  <xsl:sequence select="id, loc"/>
  <RecordNumber><xsl:value-of select="$dayNo"/></RecordNumber>
  <WorkerDays>1</WorkerDays>
  <StartDate>
    <xsl:value-of select="xs:date(StartDate) + xs:dayTimeDuration('P1D') * 
($dayNo - 1)"/>
  </StartDate>
</Worker>
</xsl:template>

<xsl:template match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>
</xsl:stylesheet>

Current output is

<?xml version="1.0" encoding="UTF-8"?>
<Workers>
<Worker>
    <id>1234</id>
    <loc>New York</loc>
    <Days>1</Days>
    <StartDate>2019-01-26</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>1</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-01</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>2</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-02</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>3</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-03</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>1</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-01</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>2</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-02</StartDate>
</Worker>
 </Workers>

I need <RecordNumber></RecordNumber> to display the sequenced numbers. Currently it's showing 1, 2, 3 and 1, 2.

Instead of this, i need 1, 2, 3, 4,5 .

Currently my XSLT code has two <for-each> loops being executed based on the values of <Days> and <Units>( pls. refer second <Worker> node in my sample input xml). i think this is why i am getting 1,2,3 and 1,2 in <RecordNumber>

I tried using position position()and declaring it as variable and use it in my template, which seems not working.

I also tried another for-each loop to execute position() which also seems to be not working

Expected Output is

<?xml version="1.0" encoding="UTF-8"?>
<Workers>
<Worker>
    <id>1234</id>
    <loc>New York</loc>
    <Days>1</Days>
    <StartDate>2019-01-26</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>1</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-01</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>2</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-02</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>3</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-03</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>4</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-01</StartDate>
</Worker>
<Worker>
    <id>2345</id>
    <loc>Boston</loc>
    <RecordNumber>5</RecordNumber>
    <WorkerDays>1</WorkerDays>
    <StartDate>2019-02-02</StartDate>
</Worker>
 </Workers>

Can someone help me find out what else i can try to get correct sequence number( <RecordNumber> please?

Upvotes: 1

Views: 450

Answers (1)

Tim C
Tim C

Reputation: 70628

Just define a variable to hold the Days value, and add that on to the dayNo parameter when you replicate the Units

<xsl:variable name="days" select="Days" />
<xsl:for-each select="1 to Units">
  <xsl:apply-templates select="$currElem" mode="replicate">
    <xsl:with-param name="dayNo" select=". + $days"/>
  </xsl:apply-templates>
</xsl:for-each>

Upvotes: 3

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