Reputation: 2394
I have a table Subscriptions in PostgreSQL 10.5:
id user_id starts_at ends_at
--------------------------------
1 233 02/04/19 03/03/19
2 233 03/04/19 04/03/19
3 296 02/09/19 03/08/19
4 126 02/01/19 02/28/19
5 126 03/01/19 03/31/19
6 922 02/22/19 03/22/19
7 111 01/22/19 02/21/19
8 111 02/22/19 03/21/19
I'd like to get a list of user ids who did not re-subscribe in march. Given the data above, it should show:
user_id
-------
296
922
How would I go about calculating this. I've given a few queries a try, but they don't work and aren't worth posting
Upvotes: 0
Views: 66
Reputation: 2341
In addition to the other answers, here a re a couple of other options:
You can create 2 CTEs, one for each month (assuming you're looking at particular months, and not just February/March in general). Note that this uses the range data type to filter the dates.
WITH
-- sample data
Subscriptions("id", user_id, starts_at, ends_at) AS
(
VALUES
(1, 233, DATE'02/04/19', DATE'03/03/19'),
(2, 233, DATE'03/04/19', DATE'04/03/19'),
(3, 296, DATE'02/09/19', DATE'03/08/19'),
(4, 126, DATE'02/01/19', DATE'02/28/19'),
(5, 126, DATE'03/01/19', DATE'03/31/19'),
(6, 922, DATE'02/22/19', DATE'03/22/19')
),
-- separate CTEs for February and March data
-- using range type for easy filter.
FebruarySubscriptions AS
(
SELECT * FROM Subscriptions
WHERE daterange('2019-02-01', '2019-03-01') @> starts_at
),
MarchSubscriptions AS
(
SELECT * FROM Subscriptions
WHERE daterange('2019-03-01', '2019-04-01') @> starts_at
)
SELECT *
FROM FebruarySubscriptions
LEFT JOIN MarchSubscriptions ON
MarchSubscriptions.user_id = FebruarySubscriptions.user_id
WHERE MarchSubscriptions."id" IS NULL
Use LEAD
window function to figure out which users don't have a re-subscription. The benefit of this option is it's more extensible.
WITH
Subscriptions("id", user_id, starts_at, ends_at) AS
(
VALUES
(1, 233, DATE'02/04/19', DATE'03/03/19'),
(2, 233, DATE'03/04/19', DATE'04/03/19'),
(3, 296, DATE'02/09/19', DATE'03/08/19'),
(4, 126, DATE'02/01/19', DATE'02/28/19'),
(5, 126, DATE'03/01/19', DATE'03/31/19'),
(6, 922, DATE'02/22/19', DATE'03/22/19')
),
Resubscriptions(user_id, current_subscription, next_subscription) AS
(
SELECT
user_id,
starts_at,
LEAD(starts_at) OVER
(
PARTITION BY user_id
ORDER BY starts_at ASC
)
FROM Subscriptions
)
SELECT *
FROM Resubscriptions
WHERE
daterange('2019-02-01', '2019-03-01') @> current_subscription
AND next_subscription IS NULL
Upvotes: 0
Reputation: 1270593
Presumably, you want a specific March, not March of any year. So:
select s.userId
from subscriptions s
group by s.userId
having count(*) filter (where startsAt >= '2019-03-01' and startsAt < '2019-04-01') = 0;
You can use not exists
as well. This works better if you have a list of users:
select u.*
from users u
where not exists (select 1
from subscriptions s
where s.userid = u.userid and
s.startsAt >= '2019-03-01' and
s.startsAt < '2019-04-01'
);
Instead of users
, you can also use:
select distinct s.userId
from subscriptions
where . . .
Upvotes: 1
Reputation: 1845
You can make use of not exists and don't get the customers who have start date of March.
with cte as
(
select 1 as ID, 233 as User_Id, '02/04/2019' as Startsat , '03/03/2019' ends_at union all
select 2 as ID, 233 as User_Id, '03/04/2019' as Startsat , '04/03/2019' ends_at union all
select 3 as ID, 296 as User_Id, '02/09/2019' as Startsat , '03/08/2019' ends_at union all
select 4 as ID, 126 as User_Id, '02/01/2019' as Startsat , '02/28/2019' ends_at union all
select 5 as ID, 126 as User_Id, '03/01/2019' as Startsat , '03/31/2019' ends_at union all
select 6 as ID, 922 as User_Id, '02/22/2019' as Startsat , '03/22/2019' ends_at)
select * from cte c
where not exists
(select 1 from cte c1 where c.User_Id = c1.User_Id and date_part('Month',to_date(c1.Startsat,'MM/DD/YYYY'))= '3' )
Output:
id user_id startsat ends_at
3 296 02/09/2019 03/08/2019
6 922 02/22/2019 03/22/2019
Here is the fiddle link:
https://dbfiddle.uk/?rdbms=postgres_10&fiddle=84e24cd517fa0810bef011d6fb1b2be2
Upvotes: 0