Reputation: 570
In my Excel sheet I have a column which gets the transposed data from a row of a different sheet.
=TRANSPOSE(DATA!L170:CC170)
An example of a cell's data is 0/300
and is consistent throughout the column.
Now I plan to have 2 new columns next to the first column to show the numbers separate:
| 0/300 | 0 | 300 |
I want the 2 columns to show their values as soon as there is data on the first column.
At first I wanted to try out the built in text to column function. But apparently it doesn't work because it only detects the formula and not the value.
Is there any other formula that can do what I want? A macro would certainly work but I'm also looking for a more simpler method if there is one.
Upvotes: 1
Views: 482
Reputation: 8220
There are two methods you could try:
Method 1
Formula for Column A:
=IFERROR(LEFT(A1,FIND("/",A1)-1),"")
Formula for Column B:
=IFERROR(MID(A1,FIND("/",A1)+1,LEN(A1)-FIND("/",A1)),"")
Results:
Method 2
Results:
Upvotes: 1
Reputation: 2201
That might be quite difficult to achieve. I guess, impossible.
Why? Because the TRANSPOSE function returns a range of a very exact size, without room to add new columns inside.
Workaround:
Add the extra-columns at the right, beyond the end of the range. Just use the LEFT / MID / RIGHT functions to get the fragments from the original text.
The workaround will work if the size of the range does not change, and if the contents are always the same in the same positions. If you want a (highly) adaptive formula, you will need to go into VBA for Excel, and that's going to be "uglier".
Edit: I took it for granted, but @MitchellDeane has a good point:
Note that you can use FIND in your left functions in case of different sizes of inputs: =LEFT(A1,(FIND("/",A1,1)-1)). Such as 0/300, 0/3000, 30/30000
Upvotes: 3