CODEWITHSUNDEEP
pythonpython-2.7list-comprehension
klex52s
klex52s

Reputation: 437

Check if List Contains Items From Another List

I realize versions of this have been asked before, but I can't find exactly what I'm looking for. I have two lists. I want to only print the items from otherList that do not contain items from firstList.

firstList = ["ABC", "DEF"]
otherList = ["ABCfoo", "foobar", "DEFfoo", "otherFooBar"]

matching = [s for s in otherList if "ABC" not in s] #Not sure how to apply this to multiple strings in a list

Desired result:

["foobar", "otherFooBar"]

Upvotes: 2

Views: 528

Answers (3)

Vaishali
Vaishali

Reputation: 38415

You can use regex,

import re

pattern = '|'.join(firstList)
matching = [word for word in otherList if not re.search(pattern, word) ]

['foobar', 'otherFooBar']

Upvotes: 1

Ian H.
Ian H.

Reputation: 21

make a copy and remove elements 

>>> matching = otherList.copy()
>>> for a in firstList:
...     for b in matching:
...             if a in b:
...                     matching.remove(b)
... 
>>> matching
['foobar', 'otherFooBar']

Upvotes: 2

Adam Smith
Adam Smith

Reputation: 54213

matching = [el for el in otherList if not any(substr in el for substr in firstList)]

You could write not any(substr in el ...) as all(substr not in el ...) if that makes more sense to you.

Upvotes: 4

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