CODEWITHSUNDEEP
javascriptecmascript-6
studiobrain
studiobrain

Reputation: 1215

es6 array return all items up to a certain conditional or the first item if all items meet condition

given the following data:

const array = [
  {name: one, completed: false},
  {name: two, completed: false},
  {name: three, completed: false},
  {name: four, completed: false},
]

const arrayTwo = [
  {name: one, completed: true},
  {name: two, completed: true},
  {name: three, completed: false},
  {name: four, completed: false},
]

I need to be able to return:

//from array
[
  {name: one, completed: false}
]

//from arrayTwo
[
  {name: one, completed: true},
  {name: two, completed: true},
  {name: three, completed: false},
]

So to the question: How can I map/filter/reduce these arrays to return all items up to and including the first one with the param meeting condition of:

completed: false

...or the first one if they all meet the condition of:

completed: false

As always any and all direction is greatly appreciated, so thanks in advance!

Upvotes: 0

Views: 39

Answers (2)

Code Maniac
Code Maniac

Reputation: 37745

You can use a simple for loop, keep pushing values to op and once you found completed return op

const array = [{name: 'one', completed: false},{name: 'two', completed: false},{name: 'three', completed: false},{name: 'four', completed: false},]

const arrayTwo = [{name: 'one', completed: true},{name: 'two', completed: true},{name: 'three', completed: false},{name: 'four', completed: false},]

const fn = arr => {
  let op = []
  for(let i=0; i<arr.length; i++){
    op.push(arr[i])
    if(!arr[i].completed){
      return op
    }
  }
}

console.log(fn(array))

console.log(fn(arrayTwo))

Upvotes: 0

Jonas Wilms
Jonas Wilms

Reputation: 138427

  const result = array.slice(0, array.findIndex(it => !it.completed) + 1);

Upvotes: 3

Related Questions