CODEWITHSUNDEEP
node.jsgulpgulp-notify
Brad Ahrens
Brad Ahrens

Reputation: 5168

Gulp-Notify Error - dest.on is not a function

I am trying to use Gulp-Notify's error handling function, but I keep getting the following error:

TypeError: dest.on is not a function

I am following the instructions here: https://www.npmjs.com/package/gulp-notify#notifyonerror but keep getting the same error.

Here is my file:

const gulp     = require('gulp');
const rename   = require('gulp-rename');
const sass     = require('gulp-sass');
const cleancss = require('gulp-clean-css');
var plumber    = require("gulp-plumber");
var through    = require('gulp-through');
var notify     = require("gulp-notify");

gulp.task('styles', function(){
    gulp.src('builders/stylesheets/style.scss')
        .pipe(sass())
        .pipe(cleancss())
        .pipe(rename('style.min.css'))
        .pipe(gulp.dest('assets/css'))
        .pipe(notify("Saved Styles!"))
        .pipe(plumber({errorHandler: notify.onError("Error: <%= error.message %>")}))
        .pipe(through(function () {
          this.emit("error", new Error("Something happend: Error message!"))
        }));
});

Any idea what it could be?

I appreciate any of the help!

Thanks!

Brad

Upvotes: 1

Views: 388

Answers (1)

d-h-e
d-h-e

Reputation: 2558

Tested your task and the error comes from your through and not from the notify.

If you delete this pipe it runs without problems. The gulp-through documentation shows an example, but i couldn't find there a usecase with pipe.

gulp.task('styles', function(cb){
    gulp.src('builders/stylesheets/style.scss')
        .pipe(sass())
        .pipe(cleancss())
        .pipe(rename('style.min.css'))
        .pipe(gulp.dest('assets/css'))
        .pipe(notify("Saved Styles!"))
        .pipe(plumber({errorHandler: notify.onError("Error: <%= error.message %>")}))

    cb();
});

Upvotes: 1

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