CODEWITHSUNDEEP
java
sUrAj
sUrAj

Reputation: 287

Find count of digits in string variable

I have a string which sometimes gives character value and sometimes gives integer value. I want to get the count of number of digits in that string.

For example, if string contains "2485083572085748" then total number of digits is 16.

Please help me with this.

Upvotes: 6

Views: 81337

Answers (9)

MoKi
MoKi

Reputation: 328

in JavaScript:

str = "2485083572085748"; //using the string in the question
let nondigits = /\D/g;  //regex for all non-digits
let digitCount = str.replaceAll(nondigits, "").length;
//counts the digits after removing all non-digits
console.log(digitCount); //see in console

Thanks --> https://stackoverflow.com/users/1396264/vedant for the Java version above. It helped me too.

Upvotes: 1

miro
miro

Reputation: 101

Just to refresh this thread with stream option of counting digits in a string:

"2485083572085748".chars()
                  .filter(Character::isDigit)
                  .count();

Upvotes: 9

Neeraj Gahlawat
Neeraj Gahlawat

Reputation: 1679

public static int getCount(String number) {
    int flag = 0;
    for (int i = 0; i < number.length(); i++) {
        if (Character.isDigit(number.charAt(i))) {
            flag++;
        }
    }
    return flag;
}

Upvotes: 2

Jigar Joshi
Jigar Joshi

Reputation: 240860

int count = 0;
for(char c: str.toCharArray()) {
    if(Character.isDigit(c)) {
        count++;
    }
}

Also see

Upvotes: 0

Vedant Agarwala
Vedant Agarwala

Reputation: 18819

A cleaner solution using Regular Expressions:

// matches all non-digits, replaces it with "" and returns the length.
s.replaceAll("\\D", "").length()

Upvotes: 28

Lucas de Oliveira
Lucas de Oliveira

Reputation: 1632

If your string gets to big and full of other stuff than digits you should try to do it with regular expressions. Code below would do that to you:

String str = "asdasd 01829898 dasds ds8898";

Pattern p = Pattern.compile("\d"); // "\d" is for digits in regex
Matcher m = p.matcher(str);
int count = 0;
while(m.find()){
   count++;
}

check out java regex lessons for more. cheers!

Upvotes: 3

Joh
Joh

Reputation: 1

Something like:

using System.Text.RegularExpressions;


            Regex r = new Regex( "[0-9]" );
            Console.WriteLine( "Matches " + r.Matches("if string contains 2485083572085748 then" ).Count );

Upvotes: -3

Prince John Wesley
Prince John Wesley

Reputation: 63688

Loop each character and count it.

    String s = "2485083572085748";
    int counter = 0;
    for(char c : s.toCharArray()) {
        if( c >= '0' && c<= '9') {
            ++counter;
        }
    }
    System.out.println(counter);

Upvotes: 2

Thomas Mueller
Thomas Mueller

Reputation: 50087

String s = "2485083572085748";
int count = 0;
for (int i = 0, len = s.length(); i < len; i++) {
    if (Character.isDigit(s.charAt(i))) {
        count++;
    }
}

Upvotes: 18

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