CODEWITHSUNDEEP
javascriptjquery
Zdenek
Zdenek

Reputation: 17

JQuery not find element which JavaScript find. Why?

This code:

if (!jQuery('#item_SwitchBoard' + index).hasClass('invisible'))
    JQuery('#item_SwitchBoard' + index).addClass('invisible');

throws exception: "Microsoft JScript - runtime error: Expected an object." (I hope that it is correct translation, because I have this message localized to my language)

but this code:

if (!jQuery('#item_SwitchBoard' + index).hasClass('invisible'))
    document.getElementById('item_SwitchBoard' + index).className = 'invisible';

works without problem.

Why?

I don't understant it. I supposed that it should be same (or analogic) thing. And how is possible that 

if (!jQuery('#item_SwitchBoard' + index).hasClass('invisible'))

works, but practicly same function:

JQuery('#item_SwitchBoard' + index).addClass('invisible');

say to me that "Expected an object.". This object has been taken by hell during milisecond or what?

I use getElementById if it works, but I interested why JQuery not works correctly in all cases. Any ideas?

It is 1.4.2 version of JQuery.

Upvotes: 1

Views: 551

Answers (3)

nfechner
nfechner

Reputation: 17525

Because capitalization is important. You need to use jQuery, not JQuery.

Upvotes: 0

tster
tster

Reputation: 18237

if (!jQuery('#item_SwitchBoard' + index).hasClass('invisible'))
    JQuery('#item_SwitchBoard' + index).addClass('invisible');

Your second line has JQuery when it should be jQuery

if (!jQuery('#item_SwitchBoard' + index).hasClass('invisible'))
    jQuery('#item_SwitchBoard' + index).addClass('invisible');

Upvotes: 0

Bob Fincheimer
Bob Fincheimer

Reputation: 18036

Could it be the capital J in JQuery? jQuery refers to an object while JQuery does not refer to an object.

Upvotes: 9

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