CODEWITHSUNDEEP
pythonuser-interfacetkinter
user11229055
user11229055

Reputation:

Python Tkinter Browsing a File- Issue

I am experiencing some issues when displaying the location of the image selected. Is there a reason why it displays <_io.TextIOWrapper name =along with mode='r'encoding ='cp1252>? I just want it to display the location of the image along with the name of the image not those extra stuff. Is there something that I am doing that is causing this to occur? Please advise.

def button(self):
    self.button = ttk.Button(self.labelFrame, text = "Upload Image", command = self.fileDialog)
    self.button.grid(column = 1, row = 1)     


def fileDialog(self):
    self.filename = filedialog.askopenfile(initialdir = "/", title = "Select a File", filetype = (("jpeg", "*.jpg"), ("All files", "*.")))
    self.label = ttk.Label(self.labelFrame, text = "")
    self.label.grid(column = 1, row = 2)
    self.label.configure(text = self.filename)

Image display

Upvotes: 1

Views: 175

Answers (1)

furas
furas

Reputation: 142631

filedialog.askopenfile gives file object, not file name.

You have to display self.filename.name instead of self.filename

Full working example

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

file_object = filedialog.askopenfile(title="Select file")
print('file_object:', file_object)
print('file_object.name:', file_object.name)
#data = file_object.read()

label = tk.Label(root, text=file_object.name)
label.pack()

root.mainloop()

Or use askopenfilename instead of askopenfile and you get file name.

Full working example

import tkinter as tk
from tkinter import filedialog

root = tk.Tk()

filename = filedialog.askopenfilename(title="Select file")
print('filename:', filename)
#data = open(filename).read()

label = tk.Label(root, text=filename)
label.pack()

root.mainloop()

Upvotes: 1

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