Reputation: 980
I have a SpringBoot 2.1.4.RELEASE RESTful Web Service app., using Spring Initializer, embedded Tomcat, Thymeleaf template engine, and package as an executable JAR file.
I have this configuration file:
@Profile("dev")
@Configuration
@EnableWebSecurity
public class DevWebSecurityConfig extends WebSecurityConfigurerAdapter {
private static final Logger LOG = LoggerFactory.getLogger(DevWebSecurityConfig.class);
@Autowired
private UserSecurityService userSecurityService;
@Autowired
private Environment env;
@Value("${server.servlet.context-path}")
private String serverContextPath;
/** The encryption SALT. */
private static final String SALT = "12323*&^%of";
@Bean
public BCryptPasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder(12, new SecureRandom(SALT.getBytes()));
}
@Override
protected void configure(HttpSecurity http) throws Exception {
final List<String> activeProfiles = Arrays.asList(env.getActiveProfiles());
if (activeProfiles.contains("dev")) {
http.csrf().disable();
http.headers().frameOptions().disable();
}
http
.authorizeRequests()
.antMatchers(publicMatchers()).permitAll()
.anyRequest().authenticated()
.and()
.formLogin().loginPage("/login").defaultSuccessUrl("/guerrilla/teatre")
.failureUrl("/login?error").permitAll()
.and()
.logout().permitAll();
}
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
auth
.inMemoryAuthentication()
.withUser("[email protected]").password("password")
.roles("ADMIN");
}
private String[] publicMatchers() {
/** Public URLs. */
final String[] PUBLIC_MATCHERS = {
"/webjars/**",
serverContextPath + "/css/**",
serverContextPath + "/js/**",
serverContextPath + "/fonts/**",
serverContextPath + "/images/**",
serverContextPath ,
"/",
"/error/**/*",
"/console/**",
SignupController.SIGNUP_URL_MAPPING,
SignupController.USER_VALIDATION_URL_MAPPING
};
return PUBLIC_MATCHERS;
}
}
but when I log in the system using the credentials: [email protected] / password I got this message on the login page : Error ! "Bad credentials"
and I see this message on the console:
2019-04-15 10:50 [http-nio-2233-exec-4] WARN o.s.s.c.b.BCryptPasswordEncoder.matches(90) - Encoded password does not look like BCrypt
I also tried using
$2y$12$EE25qVSZ2Td1D5k9mFHoYubKRqrRqCUGuwnLc9aNjosKMLeY/7/72 that is the Bcrypt of password, but neverheless I got the same error:
Encoded password does not look like BCrypt
Upvotes: 2
Views: 717
Reputation: 81
Try this.
@Override
public UserDetails loadUserByUsername(String userName) throws UsernameNotFoundException {
User user = userRepository.findByuserName(userName);
if (user == null) {
throw new UsernameNotFoundException("userName" + userName + "Not found in the database");
}
return new org.springframework.security.core.userdetails.User(user.getName(), new BCryptPasswordEncoder().encode(user.getPassword()), getGrantedAuth(user));
}
Upvotes: 1
Reputation: 1027
You must specify the encrypted password and not the raw password.
Also make sure that the encrypted password starts with "$2a$" since 2a is the only version that the BCryptPasswordEncoder accepts.
The spring security version 5.2.0.M1 supports 2a, 2b and 2y.
Upvotes: 5