Reputation: 5781
I am trying to put every path of a folder structure I need to be created into a list and then create all of them with os.makedirs()
but something goes wrong. Only the Head-Folders are created, not the Sub-Folders.
def output_folders(trcpaths):
#trcpath is a list with several paths, example: ['/home/usr/folder1', '/home/usr/folder2']
global outputfolders
outputfolders = []
#Create Paths
for x, j in enumerate(trcpaths):
for i in os.listdir(trcpaths[x]):
if i.endswith('trc'):
folderpath1 = (j + '/' + i).split('.')[0] #/home/usr/folder1/outputfolder
folderpath2 = folderpath1 + '/Steps' #/home/usr/folder1/outputfolder/Steps
folderpath3 = folderpath2 + '/Step_1' #/home/usr/folder1/outputfolder/Steps/Step_1
folderpath4 = folderpath2 + '/Step_2'
folderpath5 = folderpath2 + '/Step_3'
folderpath6 = folderpath2 + '/Step_4'
folderpath7 = folderpath2 + '/Threshold'
outputfolders.append(folderpath1)
outputfolders.append(folderpath2)
outputfolders.append(folderpath3)
outputfolders.append(folderpath4)
outputfolders.append(folderpath5)
outputfolders.append(folderpath6)
outputfolders.append(folderpath7)
#Create Folders
for j, i in enumerate(outputfolders):
print(i)
if os.path.exists(i):
if j == 0:
input('The Output-Folder already exists! Overwrite?' )
shutil.rmtree(i)
os.makedirs(i)
Although when I print(i)
the right folderpaths are printed but only the "Head-Folderpaths" are created like /home/usr/folder1/outputfolder
and not all subsequent folderpaths. Why so?
This is what I get:
/home/usr/folder1/outputfolder
/home/usr/folder2/outputfolder
But this is what I need:
/home/usr/folder1/outputfolder
/home/usr/folder1/outputfolder/Steps
/home/usr/folder1/outputfolder/Steps/Step_1
/home/usr/folder1/outputfolder/Steps/Step_2
/home/usr/folder1/outputfolder/Steps/Step_3
/home/usr/folder1/outputfolder/Steps/Step_4
/home/usr/folder1/outputfolder/Steps/Threshold
/home/usr/folder2/outputfolder
/home/usr/folder2/outputfolder/Steps
/home/usr/folder2/outputfolder/Steps/Step_1
/home/usr/folder2/outputfolder/Steps/Step_2
/home/usr/folder2/outputfolder/Steps/Step_3
/home/usr/folder2/outputfolder/Steps/Step_4
/home/usr/folder2/outputfolder/Steps/Threshold
Upvotes: 1
Views: 1050
Reputation: 17007
to keep your logic and your coding, with this code:
for j, i in enumerate(outputfolders):
print(i)
if os.path.exists(i):
if j == 0:
input('The Output-Folder already exists! Overwrite?' )
shutil.rmtree(i)
os.makedirs(i)
you dont create folder..you only delete the existing folder and recreate if it already exists
i'll add else to complete the operation:
for j, i in enumerate(outputfolders):
print(i)
if os.path.exists(i):
if j == 0:
input('The Output-Folder already exists! Overwrite?' )
shutil.rmtree(i)
os.makedirs(i)
else:
os.makedirs(i)
Upvotes: 1
Reputation: 23815
Try this (Tested on my Windows machine but should work on Linux as well)
import os
NUM_OF_STEPS = 5
def make_output_folders(trc_paths):
output_folders = []
for idx, path in enumerate(trc_paths):
for leaf in os.listdir(path):
if leaf.endswith('trc') and os.path.isdir(os.path.join(path, leaf)):
trc_folder = os.path.join(path, leaf)
output_folders.append(os.path.join(trc_folder, 'output_folder', 'Steps'))
steps_folder = output_folders[-1]
for x in range(1, NUM_OF_STEPS):
output_folders.append(os.path.join(steps_folder, 'Step_{}'.format(x)))
output_folders.append(os.path.join(trc_folder,'output_folder', 'Threshold'))
for _path in output_folders:
print(_path)
if not os.path.exists(_path):
os.makedirs(_path)
output_folders = []
# 'folder_1' contains a sub folder named '1_trc'
# 'folder_2' contains a sub folder named '2_trc'
make_output_folders(['c:\\temp\\55721430\\folder1', 'c:\\temp\\55721430\\folder2'])
Upvotes: 0