CODEWITHSUNDEEP
python
MaxB
MaxB

Reputation: 458

Sort Individual Elements of a List

I am trying to sort the individual elements of a list, but not necessarily the entire list.

Given the following list

L = ['A,X,D' , 'Q,A' , 'A,C,B']

I want to sort the individual elements alphabetically giving so that it looks like the following 

L = ['A,D,X' , 'A,Q', 'A,B,C']

I tried

L = sorted(L, key = lambda x: x[0])

Upvotes: 1

Views: 235

Answers (4)

Amir Shabani
Amir Shabani

Reputation: 4197

You want to sort a list of strings based on each string.

First you need to convert the strings into list, like this:

list_of_lists = [l.split(',') for l in L]

output:
[['A', 'X', 'D'], ['Q', 'A'], ['A', 'C', 'B']]

Then, you want to sort each list:

sorted_lists = [sorted(l) for l in list_of_lists]

output:
[['A', 'D', 'X'], ['A', 'Q'], ['A', 'B', 'C']]

Now that we've sorted each list, we want to convert the inner lists back to string (we can use join):

list_of_strings = [','.join(l) for l in sorted_lists]

output:
['A,D,X', 'A,Q', 'A,B,C']

Or you can do it all in one line, like this:

sorted_strings = [','.join(sorted(l.split(','))) for l in L]

output:
['A,D,X', 'A,Q', 'A,B,C']

Upvotes: 0

C.Nivs
C.Nivs

Reputation: 13106

You need to sort each part of the list:

L = ['A,X,D' , 'Q,A' , 'A,C,B']

L2 = [','.join(sorted(x.split(','))) for x in L]

L2
# ['A,D,X', 'A,Q', 'A,B,C']

If you don't use split, you will be sorting with commas included, which has a lower lexicographic value than alphabetical characters:

sorted(L[0])
# ',', ',', 'A', 'D', 'X'

join will put the commas back in their original places

Upvotes: 2

Ajax1234
Ajax1234

Reputation: 71451

You can use str.split with sorted:

L = ['A,X,D' , 'Q,A' , 'A,C,B']
new_l = [','.join(sorted(i.split(','))) for i in L]

Output:

['A,D,X', 'A,Q', 'A,B,C']

Upvotes: 3

brunns
brunns

Reputation: 2764

Try:

L = [",".join(sorted(l.split(","))) for l in L]

Upvotes: 3

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