CODEWITHSUNDEEP
pythonpython-3.x
Florent
Florent

Reputation: 1928

How to return to a different function in Python?

In this example I call fun3() in fun2(), but if something special happen in fun3() is there a way to directly return to fun1()? without having to check this special thing in fun2().

def fun1(num):

  res = fun2(num)

  # do something if fun3() return an error...

def fun2(num):

  res = fun3(num) # if fun3(num) return a status:error return to fun(1)

  # something else...

def fun3(num):

  if type(num) is not int:

    return {'status': 'error'}

  else: 

    # something else...

Upvotes: 0

Views: 42

Answers (1)

Tom Lubenow
Tom Lubenow

Reputation: 1161

This is what exceptions are for

def fun1(num):
  try:
    res = fun2(num)
  except Exception:
    # specific exception handling
  # will continue executing

  # something else...

def fun2(num):

  res = fun3(num) # if fun3(num) return a status:error return to fun(1)

  # something else...

def fun3(num):

  if type(num) is not int:

    raise Exception('Status Error')

  else: 

    # continue

You should consider using a specific Exception type, rather than just Exception. Fitting for this problem would be a TypeError.

Upvotes: 4

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