CODEWITHSUNDEEP
javaregex
Nexussim Lements
Nexussim Lements

Reputation: 787

Java Regex capture first group of slashes

I have the following urls

/es-es/Replica-2300/saliffanag/winsrow
/es-de/Bat-00/saliffanag/winsrow
/es-it/Re-2300/saliffanag/winsrow
/es-../
etc..

And I need a pattern that captures only /es-es/ or /es-de/ or /es-it/ (the first /...-.../) in Java.

I've tried with this 

"[^/]*/([^/]*)/"

But is not working

How can I achieve this?

Upvotes: 1

Views: 285

Answers (3)

Starmixcraft
Starmixcraft

Reputation: 397

Just use a split:

"/es-es/Replica-2300/saliffanag/winsrow".split("/", 3)[1]

returns "es-es" after that just add the / back on

For variable URLs:

String[] split = "padding/test/for/loop/es-es/Replica-2300/saliffanag/winsrow".split("/");
String result = "";  

for(String s : split){
  if(s.length() != 5){ continue;} 
  if(s.charAt(2) == '-'){
    result = s; //if you need the '/' just use result = "/" + s "/";
    break;
  }
}

Upvotes: 3

Damien O'Reilly
Damien O'Reilly

Reputation: 992

\/([a-z]{2}-[a-z]{2})\/

See here: https://regexr.com/4chaj

Regexr will explain in detail how this particular regex is working. Just click on 'Explain'

Upvotes: 0

Nikolas
Nikolas

Reputation: 44388

Here you go:

\/(es-[a-z]+)\/

Try the expression out at Regex101.

  • \/ matches the / literally - must be escaped
  • () is the capturing group
  • es- matches self literally
  • [a-z]+ matches one or more letters together

If the input might be ex. it-it, you want to use \/(\[a-z\]+-\[a-z\]+)\/.

On the other hand, if you have a defined list of the possible suffixes, use \/(es-(?:es|de|it))\/ where (?:) is a non-capturing group.

Upvotes: 1

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