CODEWITHSUNDEEP
pythonregex
Pradeep
Pradeep

Reputation: 655

How to replace multiple values in matching pattern from string

I want to search a pattern in a string and then again search some invalid character in matching pattern and then remove them or replace with some valid characters.

I have some sample dictionaries eg. sample_dict = {"randomId":"123y" uhnb\n g", "desc": ["sample description"]}

In this case I want to find the value of a dictionary let say "123y" uhnb\n g" and then remove invalid characters in it such as (", \t, \n) etc.. what I have tried is stored all the dictionaries in a file then read file and matching pattern for dictionary value, but this gives me a list of matching pattern, I can also compile these matches but I am not sure how to perform replace in original dictionary value so my final output will be: {"randomId":"123y uhnb g", "desc": ["sample description"]}

pattern = re.findall("\":\"(.+?)\"", sample_dict)

expected result: 

{"randomId":"123y uhnb g", "desc": ["sample description"]}

actual result: 

['123y" uhnb\n g']

Upvotes: 1

Views: 62

Answers (1)

Devesh Kumar Singh
Devesh Kumar Singh

Reputation: 20500

You can just substitute non-alphanumeric characters in your value using re.sub as below

dct = {"randomId":"123y uhnb\n g", "desc": ["sample description"]}
import re

for key, value in dct.items():
    val = None
    #If the value is a string, directly substitute
    if isinstance(value, str):
       val = re.sub(r"[^a-zA-Z0-9 ]", '', str(value))
    #If value is a list, substitute for all string in the list
    elif isinstance(value, list):
       val = []
       for item in value:
           val.append(re.sub(r"[^a-zA-Z0-9]", ' ', str(item)))
    dct[key] = val

print(dct)
#{'randomId': '123y uhnb g', 'desc': ['sample description']}

Upvotes: 1

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