CODEWITHSUNDEEP
matchglob
sininen
sininen

Reputation: 563

Match all files that are inside a folder and ignore one folder inside

I have the following directory structure:

root
├─ files
│  ├─ folder1
│  │  ├─ file1.js
│  |  └─ file2.js
│  ├─ folder2
│  │  └─ file3.js
│  ├─ file4.js
|  └─ file5.js
└─ config.js

How can I match every file inside of file (and subdirectories) except the files that are in folder1, in this case file3.js, file4.js and file5.js? I know I could exclude folder1 with the following: files/!(folder1)/*.js, but this only matches file3.js.

Upvotes: 0

Views: 737

Answers (2)

Domajno
Domajno

Reputation: 637

Try **/files/{*.js,!(folder1)*/*.js}. You can test using globster.xyz

Upvotes: 1

L0ngSh0t
L0ngSh0t

Reputation: 381

There is probably a more elegant way to do this as I am not too familiar with glob, but I think this will get what you are asking for. 

import glob

exclude_pattern = ['folder1']
file_list = glob.glob('./files/**/*',  recursive=True)

for pattern in exclude_pattern:
    exclude_patternmatch = list(filter(lambda x: pattern in x, file_list))
    for item in exclude_patternmatch:
        file_list.remove(item)

print(file_list)

output:

['./files/file6.js', './files/file5.js', './files/folder2/file3.js', './files/folder2/file4.js']

Upvotes: 1

Related Questions