CODEWITHSUNDEEP
javascriptdatetimemomentjsdate-rangemoment-range
Saim Abdullah
Saim Abdullah

Reputation: 304

Split a datetime range in individual day slots e.g. access the number of minutes for each individual day present in a datetime range

I have a start date object and an end date object in javascript e.g.

var startDate = moment("2019-04-22T09:20:00+05:00");
var endtDate = moment("2019-04-25T11:00:00+05:00");

now I want to have an output like this

[880,1440,660] //array for the numbers of minutes for each day present in the given range

I have tried something using moment range module but still in vain

Thanks for the help in advance

Upvotes: 1

Views: 2353

Answers (2)

Syed Mehtab Hassan
Syed Mehtab Hassan

Reputation: 1337

Try this code simply calculate minutes for start and end date and push 1440 minutes for between dates by calculating days between two dates

function getMinutes(dt1, dt2) {
  minuteArray = [];

  // hours*minutes*seconds*milliseconds
  var oneDay = 24 * 60 * 60 * 1000; 

  startHours = (24 - dt1.getHours())
  if (dt1.getMinutes() > 0) {
    startHours--;
  }

  // Calculate Minutes for start date
  startDayMin = startHours * 60 + (60 - dt1.getMinutes());

  minuteArray.push(startDayMin);
  var diffDays = Math.round(Math.abs((dt1.getTime() - dt2.getTime()) / (oneDay))) - 1; //Calculate number of days

  for (i = 0; i < diffDays; i++) {
   
    //Push minutes for number of days
    minuteArray.push(1440);

  }

 if (diffDays >= 0){
   // Calculate Minutes for end date
    endDayMin = (dt2.getHours()* 60) + dt2.getMinutes();

    minuteArray.push(endDayMin)
}
  return minuteArray;
}



var startDate = new Date("2019-04-22T09:20:00+05:00");
var endtDate = new Date("2019-04-25T11:00:00+05:00");
console.log(getMinutes(startDate, endtDate));

Upvotes: 0

Syed mohamed aladeen
Syed mohamed aladeen

Reputation: 6755

Try this code.

var startDate = moment("2019-04-22T09:20:00+05:00");
var endDate = moment("2019-04-25T11:00:00+05:00");

var duration = moment.duration(endDate.diff(startDate));
var days = Math.round(duration.asDays());


var start,end;
var minutes = [];

for(i = 0; i<=days; i++){
  if(i == 0){
    start = startDate;
    end = moment(startDate).endOf("day").utcOffset("+05:00");
  }else if(i == days){
    start = moment(endDate).startOf('day').utcOffset("+05:00");
    end = endDate;
  } else {
    start = moment(startDate).add('days', i).startOf('day').utcOffset("+05:00");
    end = moment(startDate).add('days', i).endOf('day').utcOffset("+05:00");
  }
  
  var duration = moment.duration(end.diff(start));
  var min = duration.asMinutes();

  minutes.push(Math.round(min))
}

console.log(minutes)
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.js"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Upvotes: 1

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