CODEWITHSUNDEEP
pythonfilepath
Dawn17
Dawn17

Reputation: 8297

Opening a relative path and writing

def generate_log(dirname, log_object):
    print(os.path.dirname(__file__),'dfsdfds')
    print(os.listdir())
    for smell in log_object:  
        log = open("../../output/logs/{}_logs".format(smell), "w")
        for elem in log_object[smell]:
            log.write('filename: {}, smelly_lines: {}, metric: {}\n'.format(elem['filename'], str(elem['lineno']), str(elem['metric'])))

My function tries to write some logs in to the directory output/logs/ The directory that I am calling this function is C:\Users\user\Desktop\proj\src\Detector. Since I want the output directory to be generated in /proj which is my project root, I thought doing ../../ would work, but it gives me

log = open("../../output/logs/{}_logs".format(smell), "w") FileNotFoundError: [Errno 2] No such file or directory: '../../output/logs/long_method_logs'

Is there anything I can do to fix this?

Upvotes: 0

Views: 57

Answers (1)

sakost
sakost

Reputation: 267

You should use the os module with its submodule os.path

For joining a paths you should do os.path.join(path1, path2)

In your case you should do something like this:

log = open(os.path.join(os.pardir, os.pardir, "output", "logs", "{}_logs").format(smell), "w")

Also you should close this file via log.close() before exit

And for this purposes there is a logging module

Upvotes: 2

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