CODEWITHSUNDEEP
pythonlistformatting
JohelPF
JohelPF

Reputation: 43

How to print a list of lists in different lines?

I'm trying to make a Pascal pyramid in python and I'm doing it with a list of lists, that way it's easier to insert the values I need it positions I need them, everything is working fine except when I print the list of lists it doesn't format correctly line by line the way I want it to

I've tried formatting with end=" ", and by using a * to unpack the list of lists however none of these seem to work


    def unos(n,fila,columna,m):
        mitad=columna//2
        m[0][4]=1
        for i in range(1,fila):
            x=mitad+i
            y=mitad-i
            m[i][x]=1
            m[i][y]=1

    **print(*m)**#The error seems to be here(I could be wrong)

Python prints m this way: [0, 0, 0, 0, 1, 0, 0, 0, 0] [0, 0, 0, 1, 0, 1, 0, 0, 0] [0, 0, 1, 0, 0, 0, 1, 0, 0] [0, 1, 0, 0, 0, 0, 0, 1, 0] [1, 0, 0, 0, 0, 0, 0, 0, 1]

However what I need it printed out is this:

[0, 0, 0, 0, 1, 0, 0, 0, 0]

[0, 0, 0, 1, 0, 1, 0, 0, 0]

[0, 0, 1, 0, 0, 0, 1, 0, 0]

[0, 1, 0, 0, 0, 0, 0, 1, 0]

[1, 0, 0, 0, 0, 0, 0, 0, 1]

Upvotes: 3

Views: 946

Answers (4)

gmds
gmds

Reputation: 19885

To answer your question, we must inspect the unpacking operator (*) and how it works with print.

Recall that the unpacking operator takes a single iterable and turns it into multiple elements which are passed in series to a function.

Then, we know that print takes multiple arguments in the form of args, using a separator to separate them, if necessary. With this in mind, we can see that the four ways to print a b c are equivalent: 

print('a', 'b', 'c')
print(*['a', 'b', 'c'])
print(sep.join(['a', 'b', 'c']))
print('a' + sep + 'b' + sep + 'c')

...where sep is, by default, (a single space).

Now, we note that m is a nested list. Therefore, by doing print(*m), what you are doing is effectively print(m[0], m[1]...m[-1]), where m[0], m[1]...m-1 are individually lists.

By referring to our analysis of print above, we can see that that is the same as print(m[0] + ' ' + m[1] + ' ' + ... + ' ' + m[-1]).

Clearly, there are no newlines in that, but there should be newlines where there are now spaces.

To get what we want, which is a newline after each element, therefore, we can just do print(*m, sep='\n').

Upvotes: 2

hossein hayati
hossein hayati

Reputation: 1158

you can use pprint:

import pprint
stuff = ['spam', 'eggs', 'lumberjack', 'knights', 'ni']
stuff.insert(0, stuff)
pprint.pprint(stuff)

result : 

 [<Recursion on list with id=...>,
 'spam',
 'eggs',
 'lumberjack',
 'knights',
 'ni']

you can see more examples here

Upvotes: 0

Netwave
Netwave

Reputation: 42678

You can use str.join to show it all together in a string:

>>> print("\n".join("".join(str(e) for e in x) for x in l))
000010000
000101000
001000100
010000010
100000001

Where l is your m

Upvotes: 1

drum
drum

Reputation: 5651

Just need individual print statements.

for l in m:
    print(l)

Upvotes: 0

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