Reputation: 527
I need to get results of this formula - a column of numbers
{x = ($1-T1)/Fi; print (x-int(x))}
from inputs file1
4 4
8 4
7 78
45 2
file2
0.2
3
2
1
From this files should be 4 outputs. $1 is the first column from file1, T1 is the first line in first column of the file1 (number 4) - it is alway this number, Fi, where i = 1, 2, 3, 4 are numbers from the second file. So I need a cycle for i from 1 to 4 and compute the term one times with F1=0.2, the second output with F2=3, then third output with F3=2 and the last output will be for F4=1. How to express T1 and Fi in this way and how to do a cycle?
awk 'FNR == NR { F[++n] = $1; next } FNR == 1 { T1 = $1 } { for (i = 1; i <= n; ++i) { x = ($1 - T1)/F[i]; print x - int(x) >"output" FNR} }' file2 file1
This gives more than 4 outputs. What is wrong please?
Upvotes: 1
Views: 55
Reputation: 50750
FNR == 1 { T1 = $1 }
is being run twice, when file2
is started being read T1
is set to 0.2
,>"output" FNR
is problematic, you should enclose the output name expression in parentheses.Here's how I'd do it:
awk '
NR==1 {t1=$1}
NR==FNR {f[NR]=$1; next}
{
fn="output"FNR
for(i in f) {
x=(f[i]-t1)/$1
print x-int(x) >fn
}
close(fn)
}
' file1 file2
Upvotes: 2