CODEWITHSUNDEEP
javascriptregex
Akhilesh Kumar
Akhilesh Kumar

Reputation: 9355

Get list of variable from string of specific format

I have a complex string which can have variable in specific format as /##{[^}{\(\)\[\]\-\+\*\/]+?}##/g I want to extract those variables in an array.

e.g.

var x= "sgsegsg##{xx}gerweg##{xx1}##rgewrgwgwrg}##ferwfwer##{xx2}rgrg##{xx3}####{xx4}####{errg}}}";

function getVariableNames (param) {
   return param.match(/(##{[^}{\(\)\[\]\-\+\*\/]+?}##)+?/g)
}

getVariableNames(x);

above lines returns ["##{xx1}##", "##{xx3}##", "##{xx4}##"]

where I want to get ['xx1', 'xx3', 'xx4']

Upvotes: 1

Views: 56

Answers (2)

Akhilesh Kumar
Akhilesh Kumar

Reputation: 9355

I tried it with following and it worked:

var x= "sgsegsg##{xx}gerweg##{xx1}##rgewrgwgwrg}##ferwfwer##{xx2}rgrg##{xx3}####{xx4}####{errg}##{xx5(}####{xx-6}####{xx7}##}}";

function getVariableNames (str) {
    let variables = str.match(/(##{[^}{)(\]\[\-+*\/]+?}##)+?/g);
    return variables && variables.length  ? variables.map(i=>i.substring(3, i.length - 3)) : false;
}

getVariableNames(x)

Upvotes: 0

CertainPerformance
CertainPerformance

Reputation: 370979

Based on your pattern, because the portion inside the ##s won't contain curly braces, simply repeating non-curly braces is enough: [^}]+. Match the repeated non-bracket characters, and then iterate through the matches and extract the captured group:

const str = "sgsegsg##{xx}gerweg##{xx1}##rgewrgwgwrg}##ferwfwer##{xx2}rgrg##{xx3}####{xx4}####{errg}}}";
const pattern = /##{([^}]+)}##/g;
let match;
const matches = [];
while (match = pattern.exec(str)) {
  matches.push(match[1]);
}
console.log(matches);

On newer environments, you can lookbehind for ##{ instead:

const str = "sgsegsg##{xx}gerweg##{xx1}##rgewrgwgwrg}##ferwfwer##{xx2}rgrg##{xx3}####{xx4}####{errg}}}";
const pattern = /(?<=##{)[^}]+(?=}##)/g;
console.log(str.match(pattern));

Upvotes: 2

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