CODEWITHSUNDEEP
asp.net-mvcautomapper
Shawn Mclean
Shawn Mclean

Reputation: 57469

Mapping Lists using Automapper

I have the classes:

public class Person{ /* Props here */ }

public class PersonViewModel { /* Props here */ }

Then the list:

List<Person> people = new List<Person>();
List<PersonViewModel> peopleVM = Mapper
                                .MapList<Person, PersonViewModel>(people); //Problem here.

What is the correct way to do this?

Upvotes: 94

Views: 151555

Answers (6)

Ranga
Ranga

Reputation: 1391

Another Solution

mapper.Map<IEnumerable<PersonViewModel>>(people);

Upvotes: 3

Jerph
Jerph

Reputation: 4570

If you're using IQueryable lists here (from EF or NH, for example) you can use the AutoMapper.IQueryableExtensions methods, Project() and To().

This is my first time with AutoMapper, but I'm succeeding by creating a map for just the model:

Mapper.CreateMap<Person, PersonViewModel>();
Mapper.AssertConfigurationIsValid();

And then using the IQueryableExtension methods Project() and To():

using AutoMapper.QueryableExtensions;
...

IQueryable<Person> people = new List<Person>().AsQueryable(); //actually from ORM
IQueryable<PersonViewModel> peopleVM = people.Project().To<PersonViewModel>();

Upvotes: 15

Derek Beattie
Derek Beattie

Reputation: 9478

Mapper.CreateMap<Person, PersonViewModel>();
peopleVM = Mapper.Map<List<Person>, List<PersonViewModel>>(people);
Mapper.AssertConfigurationIsValid();

From Getting Started:

How do I use AutoMapper?

First, you need both a source and destination type to work with. The destination type's design can be influenced by the layer in which it lives, but AutoMapper works best as long as the names of the members match up to the source type's members. If you have a source member called "FirstName", this will automatically be mapped to a destination member with the name "FirstName". AutoMapper also supports Flattening, which can get rid of all those pesky null reference exceptions you might encounter along the way.

Once you have your types, and a reference to AutoMapper, you can create a map for the two types.

Mapper.CreateMap<Order, OrderDto>();

The type on the left is the source type, and the type on the right is the destination type. To perform a mapping, use the Map method.

OrderDto dto = Mapper.Map<Order, OrderDto>(order);

Upvotes: 116

ruudj
ruudj

Reputation: 31

In core 1.1 this extension might work:

public static List<TDestination> MapList<TSource, TDestination>(this IMapper mapper, List<TSource> source)
        {
            return source.Select(x => mapper.Map<TDestination>(x)).ToList();
        }

Upvotes: 3

garryp
garryp

Reputation: 5766

You could create an extension method to do something like this using existing mappings for individual items:

public static class AutoMapperExtensions
{
    public static List<TDestination> MapList<TSource, TDestination>(this IMapper mapper, List<TSource> source)
    {
        return mapper.Map<List<TDestination>>(source);
    }
}

Usage:

List<PersonViewModel> peopleVM = _mapper.MapList<PersonViewModel>(people);

Upvotes: 0

Ram
Ram

Reputation: 16814

Another Solution

List<Person> people = new List<Person>();
List<PersonViewModel> peopelVM;
peopelVM = people.Select(Mapper.Map<Person, PersonViewModel>);

And in the Automapper config

Mapper.CreateMap<Person, PersonViewModel>();

Upvotes: 30

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