CODEWITHSUNDEEP
sqlregexoracle-database
Sid
Sid

Reputation: 582

How to identify combination of number and character in SQL

I have a requirement where I have to find number of records in a special pattern in the field ref_id in a table. It's a varchar column. I need to find all the records where 8th, 9th and 10th character are numeric+XX. That is it should be like 2XX or 8XX. I tried using regexp :digit: but no luck. Essentially I am looking for all records where 8th-10th characters are 1XX, 2XX, 3XX… etc

Upvotes: 1

Views: 1070

Answers (3)

RayCW
RayCW

Reputation: 184

No need for a regexp:

select * from mytable where substr(ref_id, 8, 3) in ('0XX','1XX','2XX','3XX','4XX','5XX','6XX','7XX','8XX','9XX')

or

select * from mytable where substr(ref_id, 8, 3) in ('1XX','2XX','3XX','4XX','5XX','6XX','7XX','8XX','9XX')

I don't know if '0XX' is a valid match or not.

Regexp's tend to be slow.

Upvotes: 0

Kaushik Nayak
Kaushik Nayak

Reputation: 31648

This can also be achieved using standard non-regex SQL functions

select * from t where s like '________XX%'     -- any 8 characters and then XX
      AND translate( substr(s,8,1),'?0123456789','?') is  null; --8th one is numeric

DEMO

Upvotes: 2

Kubator
Kubator

Reputation: 1383

Using REGEXP_LIKE, replace table with Yours:

SELECT COUNT(*)
FROM table
WHERE REGEXP_LIKE(ref_id,'^.{7}[0-9]XX');

.{7} whatever seven characters

[0-9] 8th character digit

XX 9th and 10th characters X

Or with [:digit:] class as You are mentioning, You may use:

SELECT COUNT(*)
FROM table
WHERE REGEXP_LIKE(ref_id,'^.{7}[[:digit:]]XX');

Upvotes: 2

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