CODEWITHSUNDEEP
pythonxpathweb-scrapingbeautifulsoupcss-selectors
DiamondJoe12
DiamondJoe12

Reputation: 1817

Using BeautifulSoup to search for element by src tag

Let's say I'm scraping a webpage, and I want to select a certain image on the webpage. Just as you can find elements based on their class name, I want to select an image by its src tag. How would I select an image where I already know the src tag?

i.e. I want to select the image whose src tag is:

https://assets.bandsintown.com/images/pin.svg

Upvotes: 0

Views: 368

Answers (4)

QHarr
QHarr

Reputation: 84465

You said a single image by its src value. Use select_one. Less work and you only need an attribute selector.

soup.select_one('[src="https://assets.bandsintown.com/images/pin.svg"]')['src']

Upvotes: 0

KunduK
KunduK

Reputation: 33384

Using Beautifulsoup you can do it many ways. You can use css selector , you can use regular expression as well.

Css Selector 

for item in soup.select('img[src="https://assets.bandsintown.com/images/pin.svg"]'):
   print(item['src'])

Regular Expression with find_all

import re
for item in soup.find_all('img',src=re.compile('https://assets.bandsintown.com/images/pin.svg')):
   print(item['src'])

Upvotes: 0

undetected Selenium
undetected Selenium

Reputation: 193308

While @Blorgbeard's answer shows the Beautifulsoup approach, using Selenium you can achieve the same using either of the following Locator Strategies:

  • css_selector:

    my_elements = driver.find_elements_by_css_selector("[src=\"https://assets.bandsintown.com/images/pin.svg\"]")

  • xpath:

    my_elements = driver.find_elements_by_xpath("//*[@src=\"https://assets.bandsintown.com/images/pin.svg\"]")

Upvotes: 1

Blorgbeard
Blorgbeard

Reputation: 103535

You can search by arbitrary attributes; this should work:

soup.findAll("img", {"src" : "https://assets.bandsintown.com/images/pin.svg"})

Upvotes: 5

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