CODEWITHSUNDEEP
groovy
SSF
SSF

Reputation: 983

Appending Elements to a List Creates List of List in Groovy

I am parsing each element of a list one by one. 

def List1 = (String[]) Data[2].split(',')

Part of this list gives me a list with elements that contain a delimiter !.

List1 = [TEST1!01.01.01, TEST2!02.02.02]

I tried to iterate each element of this list and obtain a comma separated list. 

          def List2 = []
          List1.each { List2.add(it.split('!'))}

However, the result was a list of list.

[[TEST1, 01.01.01], [TEST2, 02.02.02]]

Instead of [TEST1, 01.01.01, TEST2, 02.02.02].

How do I avoid this and obtain a list as shown above?

Upvotes: 2

Views: 542

Answers (3)

SSF
SSF

Reputation: 983

split() returns a list. That is the reason why I got a list of list. I found that split() can carry process multiple delimiters as well when applied with an operator. The following returns the desired output.

def List1 = (String[]) Data[2].split(',|!')

Upvotes: 0

Jakov
Jakov

Reputation: 1009

When you do List2.add(it.split('!')), you are adding list to List2 instead of single string because .split() creates a list from string.

You should firstly create list by using .split() and than add each member of list to List2.

Here is solution:

def List1 = ["TEST1!01.01.01", "TEST2!02.02.02"]

​def List2 = []          

List1.each { List1member ->
    def subList = List1member.split('!')
    subList.each { subListMember ->
        List2.add(subListMember)
    } 
}

println(List2)​

Upvotes: 1

Rao
Rao

Reputation: 21389

How about this?

def list1 = ['TEST1!01.01.01', 'TEST2!02.02.02']
println list1.collect{it.split('!')}.flatten()

Upvotes: 2

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