Reputation: 167
I am trying to read a xlsx
file, compare all the reference numbers from a column to files inside a folder and if they correspond, rename them to an email associate with the reference number.
Excel File has fields such as:
Reference EmailAddress
1123 [email protected]
1233 [email protected]
1334 [email protected]
... .....
My folder applicants
just contains doc files named as the Reference column:
How can I compare the contents of the applicantsCVs
folder, to the Reference field inside my excel file and if it matches, rename all of the files as the corresponding email address ?
Here is What I've tried so far:
import os
import pandas as pd
dfOne = pd.read_excel('Book2.xlsx', na_values=['NA'], usecols = "A:D")
references = dfOne['Reference']
emailAddress = dfOne['EmailAddress']
cleanedEmailList = [x for x in emailAddress if str(x) != 'nan']
print(cleanedEmailList)
excelArray = []
filesArray = []
for root, dirs, files in os.walk("applicantCVs"):
for filename in files:
print(filename) #Original file name with type 1233.doc
reworkedFile = os.path.splitext(filename)[0]
filesArray.append(reworkedFile)
for entry in references:
excelArray.append(str(entry))
for i in excelArray:
if i in filesArray:
print(i, "corresponds to the file names")
I compare the reference names to the folder contents and print it out if it's the same:
for i in excelArray:
if i in filesArray:
print(i, "corresponds to the file names")
I've tried to rename it with os.rename(filename, cleanedEmailList )
but it didn't work because cleanedEmailList
is an array of emails.
How can I match and rename the files?
Update:
from os.path import dirname
import pandas as pd
from pathlib import Path
import os
dfOne = pd.read_excel('Book2.xlsx', na_values=['NA'], usecols = "A:D")
emailAddress = dfOne['EmailAddress']
reference = dfOne['Reference'] = dfOne.references.astype(str)
references = dict(dfOne.dropna(subset=[reference, "EmailAddress"]).set_index(reference)["EmailAddress"])
print(references)
files = Path("applicantCVs").glob("*")
for file in files:
new_name = references.get(file.stem, file.stem)
file.rename(file.with_name(f"{new_name}{file.suffix}"))
Upvotes: 2
Views: 4225
Reputation: 1
Step 1: import the data from excel sheet "Book1.xlsx"
import pandas as pd
df = pd.read_excel (r'path of your file here\Book1.xlsx')
print (df)
Step 2: Choose path that your ".docx"
files are in and store their names.
Get only relevent part of filename to compare.
mypath = r'path of docx files\doc files'
from os import listdir,rename
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]
#print(onlyfiles)
currentfilename=onlyfiles[0].split(".")[0]
This is how I stored the files
Step 3: Run loop to check if name matches with the Reference. And just use rename(src,dest)
function from os
for i in range(3):
#print(currentfilename,df['ref'][i])
if str(currentfilename)==str(df['Reference'][i]):
corrosponding_email=df['EmailAddress'][i]
#print(mypath+"\\"+corrosponding_email)
rename(mypath+"\\"+str(currentfilename)+".docx",mypath+"\\"+corrosponding_email+".docx")
checkout the code with example:https://github.com/Vineet-Dhaimodker
Upvotes: 0
Reputation: 1314
Let consider our sample data in excel sheet is following:
Reference EmailAddress
1123 [email protected]
1233 [email protected]
1334 [email protected]
nan [email protected]
There are following steps involved to solve this problem.
import the data properly from excel sheet "my.xlsx"
. Here I am using the sample data
import pandas as pd
import os
#import data from excel sheet and drop rows with nan
df = pd.read_excel('my.xlsx').dropna()
#check the head of data if the data is in desirable format
df.head()
You will see that the data type in the references are in float type here
Change the data type in the reference column to integer and then into string
df['Reference']=df.Reference.astype(int, inplace=True)
df = df.astype(str,inplace=True)
df.head()
Now the data is in desirable format
Renaming the files in the desired folder. Zip the lists of 'Reference' and 'EmailAddress' to use in for loop.
#absolute path to folder. I consider you have the folder "application cv" in the home directory
path_to_files='/home/applicant cv/'
for ref,email in zip(list(df['Reference']),list(df['EmailAddress'])):
try:
os.rename(path_to_files+ref+'.doc',path_to_files+email+'.doc')
except:
print ("File name doesn't exist in the list, I am leaving it as it is")
Upvotes: 0
Reputation: 4482
You could do it directly in your dataframe using df.apply()
:
import glob
import os.path
#Filter out null addresses
df = df.dropna(subset=['EmailAddress'])
#Add a column to check if file exists
df2['Existing_file'] = df2.apply(lambda row: glob.glob("applicantsCVs/{}.*".format(row['Reference'])), axis=1)
df2.apply(lambda row: os.rename(row.Existing_file[0], 'applicantsCVs/{}.{}'.format( row.EmailAddress, row.Existing_file[0].split('.')[-1])) if len(row.Existing_file) else None, axis = 1)
print(df2.Existing_file.map(len), "existing files renamed")
EDIT :
works now with any extension (.doc
, .docx
) by using glob
module
Upvotes: 0
Reputation: 82765
This is one approach using a simple iteration.
Ex:
import os
#Sample Data#
#dfOne = pd.DataFrame({'Reference': [1123, 1233, 1334, 4444, 5555],'EmailAddress': ["[email protected]", "[email protected]", "[email protected]", np.nan, "[email protected]"]})
dfOne = pd.read_excel('Book2.xlsx', na_values=['NA'], usecols = "A:D")
dfOne.dropna(inplace=True) #Drop rows with NaN
for root, dirs, files in os.walk("applicantsCVs"):
for file in files:
file_name, ext = os.path.splitext(file)
email = dfOne[dfOne['Reference'].astype(str).str.contains(file_name)]["EmailAddress"]
if email.values:
os.rename(os.path.join(root, file), os.path.join(root, email.values[0]+ext))
Or if you have only .docx
file to rename
import os
dfOne = pd.read_excel('Book2.xlsx', na_values=['NA'], usecols = "A:D")
dfOne["Reference"] = dfOne["Reference"].astype(str)
dfOne.dropna(inplace=True) #Drop rows with NaN
ext = ".docx"
for root, dirs, files in os.walk("applicantsCVs"):
files = r"\b" + "|".join(os.path.splitext(i)[0] for i in files) + r"\b"
for email, ref in dfOne[dfOne['Reference'].astype(str).str.contains(files, regex=True)].values:
os.rename(os.path.join(root, ref+ext), os.path.join(root, email+ext))
Upvotes: 0
Reputation: 7058
based on sample data:
Reference EmailAddress
1123 [email protected]
1233 [email protected]
nan jane.smith#example.com
1334 [email protected]
First you assemble a dict
with the set of references as keys and the new names as values:
references = dict(df.dropna(subset=["Reference","EmailAddress"]).set_index("Reference")["EmailAddress"])
{'1123': '[email protected]', '1233': '[email protected]', '1334': '[email protected]'}
Note that the references are str
s here. If they aren't in your original database, you can use astype(str)
Then you use pathlib.Path
to look for all the files in the data directory:
files = Path("../data/renames").glob("*")
[WindowsPath('../data/renames/1123.docx'), WindowsPath('../data/renames/1156.pptx'), WindowsPath('../data/renames/1233.txt')]
The renaming can be made very simple:
for file in files:
new_name = references.get(file.stem, file.stem )
file.rename(file.with_name(f"{new_name}{file.suffix}"))
The references.get
asks for the new filename, and if it doesn't find it, use the original stem.
[WindowsPath('../data/renames/1156.pptx'), WindowsPath('../data/renames/[email protected]'), WindowsPath('../data/renames/[email protected]')]
Upvotes: 3
Reputation: 647
How about adding the "email associate" (your new name i guess?) into an dictionary, where the keys are your reference numbers? This could look something like:
cor_dict = {}
for i in excelArray:
if i in filesArray:
cor_dict[i] =dfOne['EmailAddress'].at[dfOne.Reference == i]
for entry in cor_dict.items():
path = 'path to file...'
filename = str(entry[0])+'.doc'
new_filename = str(entry[1]).replace('@','_') + '_.doc'
filepath = os.path.join(path, filename)
new_filepath = os.path.join(path,new_filename)
os.rename(filename, new_filename)
Upvotes: 0