Trouble finding syntax error in bash script?

Question

The program is meant to create a random number and check if it is lesser than, greater than or equal to the number that the user inputs while the count is less than 3.

#!/bin/sh
ranNum=$(($RANDOM % (2 - 1)))
ranNum=$((1 + $ranNum))
c=1

echo "The entity with the greatest number wins"
while [ $c -lt 3 ]
do
    echo "Enter a number"
    read usrIn
    if ["$usrIn" -gt "$ranNum"]
    then
        echo "You won"
        ((c++))
    if ["$usrIn" -lt "$ranNum"]
    then
        echo "You lost"
        ((c++))
    else
        echo "Its a tie"
        ((c++))
        break
    fi
done

When I run the code in the shell I get 2 errors returned:

line 24: syntax error near unexpected token done' line 24:done'

I'm not sure what's wrong with the syntax of my code or where to go from here.

Answer 1

The second "if" statement should be "elif"