CODEWITHSUNDEEP
c#
Bramble
Bramble

Reputation: 1395

Open a resource file with StreamReader?

This doesnt work:

string fileContent = Resource.text;
    StreamReader read = File.OpenText(fileContent);

    string line;
            char[] splitChar = "|".ToCharArray();

            while ((line = read.ReadLine()) != null)
            {
                string[] split = line.Split(splitChar);
                string name = split[0];
                string lastname = split[1];

            }

            read.Dispose();

How do you open a resource file to get its contents?

Upvotes: 3

Views: 10414

Answers (3)

Arnaud F.
Arnaud F.

Reputation: 8462

to read resources, you need a special Stream named "ResourceReader", you can use it like this :

string fileContent = "<your resource file>";

using (ResourceReader reader = new ResourceReader(fileContent))
{
    foreach (IDictionaryEnumerator dict in reader)
    {
        string key = dict.Key as string;
        object val = dict.Value;
    }
}

Upvotes: 0

Darin Dimitrov
Darin Dimitrov

Reputation: 1039428

Try like this:

string fileContent = Resource.text;
using (var reader = new StringReader(fileContent))
{
    string line;
    while ((line = reader.ReadLine()) != null)
    {
        string[] split = line.Split('|');
        string name = split[0];
        string lastname = split[1];
    }
}

Upvotes: 5

Hendry Ten
Hendry Ten

Reputation: 1092

I think the variable fileContent already has all the contents you need.

Upvotes: 0

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