CODEWITHSUNDEEP
javascriptregex
Dwight
Dwight

Reputation: 13

How to check for Forward Slash within this Regex for all special characters?

I am trying to find a regex solution to check if a string matches all conditions + / forward slashes.

Current code:

var specialChars = /^[a-zA-Z0-9!@#\$%\^\&*\)\(+=._-]+$/g;

This will match true if a string looks like so: 4!@#$.

However it does not work if the string looks like this: 5/6/2019

This is how I'm implementing this check, basically I have a function that takes in an long string. And what I'm trying to do is pluck out the tracking ID then create a link out of it.

My test cases are also in the demo, the date test is the one that fails, since the linkCreator function ends up linking to the date:

https://jsfiddle.net/cojuevp5/

var linkCreator = function(value) {
  var strings = value.split(' ');
  var aHref = '<a href="http://www.google.com/search?q=';
  var targetBlank = '" target="_blank" style="text-decoration: underline">';

  var trackingString = strings.reduce(function(prevVal, currVal, idx) {
    var specialChars = /^[a-zA-Z0-9!@#\$%\^\&*\)\(+=._-]+$/g;
    // Does val start with number and not contain special characters including /
    var link = currVal.match(/^\d/) && !currVal.match(specialChars) ?
      aHref + currVal + targetBlank + currVal + '</a>' :
      currVal;
    return idx == 0 ? link : prevVal + ' ' + link;
  }, '');

  console.log(trackingString);
}

const case1 = '434663008870'
const case2 = '4S4663008870'
const case3 = '4S4663008870 PS'
const case4 = 'SHD FX 462367757727 PS'
const case5 = 'SHD FX 429970755485, R'
const case6 = 'SHD HEADER TRACKING PS'
const case7 = 'N/A'
const case8 = 'AF SHD FX 462367757727 PS'
const case9 = '4/7/2019'
const case10 = '4!@#$%^&'

const value = case9

const link = linkCreator(value)
console.log(link)

Upvotes: 1

Views: 59

Answers (1)

Emma
Emma

Reputation: 27723

You might want to add a \/ and that would likely solve your problem:

^([A-z0-9!\/@#$%^&*)(+=._-]+)$

Just like Barmar says, you do not need to escape all chars inside []:

I'm guessing that this may be what you might want to match:

enter image description here

You might just use this tool and design any expression that you wish.

Graph

This graph shows how your expression works:

enter image description here

Upvotes: 1

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