Reputation: 1459
I cannot convert JSON to Kotlin data class using Gson due to the MutableMap object. The data class
data class MyAction(
@Key("action") var action: String = "default",
@Key("data") var data: MutableMap<String, Any> = mutableMapOf()
)
values in the data
map are of several types.I tried with TypeToken and Generics, as in here but didn't work. Examples of received json:
{"action":"playVideo","data":{"media":{"id":15060328,"url":"http://url_to_get_item","name":"item name","shortDescription":"short desc"}
{"action":"setSpeed","data":{"value":1}}
{"action":"getProperty","data":{"value":"position"}}
Upvotes: 3
Views: 1530
Reputation: 839
Is not a good practice to design data in that way, but if you have no control on backend here is an example how to deserialize this
class MyDeserializer : JsonDeserializer<MyAction>{
override fun deserialize(json: JsonElement, typeOfT: Type, context: JsonDeserializationContext): MyAction {
val myAction = MyAction()
val action = json.asJsonObject.get("action")
val data = json.asJsonObject.get("data")
myAction.action = context.deserialize<String>(action, String::class.java)
val myMap = mutableMapOf<String, Any>()
data.asJsonObject.keySet().forEach {
when (it) {
is String -> { myMap[it] = context.deserialize(data.asJsonObject.get(it), String::class.java) }
is MyCustomObject1 -> { myMap[it] = context.deserialize(data.asJsonObject.get(it), MyCustomObject1::class.java) }
is MyCustomObject2 -> { myMap[it] = context.deserialize(data.asJsonObject.get(it), MyCustomObject2::class.java) }
else -> myMap[it] = context.deserialize(data.asJsonObject.get(it), Any::class.java)
}
}
myAction.data = myMap
return myAction
}
}
Dont forget to register your deserializer
fun getSmartGson() = GsonBuilder().registerTypeAdapter(MyAction::class.java, MyDeserializer())
Upvotes: 2