CODEWITHSUNDEEP
phpjqueryhtml
RiotAct
RiotAct

Reputation: 773

Saving Radio Button Inputs into Array

I am working on a custom survey that is dynamically populated with database information and needs to be saved as an array. I can make everything work as it should except I would like to use a star rating system for many of the answers and it seems radio buttons won't work like this:

<input type="radio" name="surveyRating[]" value="1" />
<input type="radio" name="surveyRating[]" value="2" />
<input type="radio" name="surveyRating[]" value="3" />
<input type="radio" name="surveyRating[]" value="4" />
<input type="radio" name="surveyRating[]" value="5" />

Because there are multiple instances of this same code. This will be saved into an array so surveyRating will be used over and over again. If I click a radio button in one group, it changes to a radio in another group.

I have read I can possibly do this with checkboxes instead. Is that the best alternative? Or is there another option I should be looking at? I want the final product to be star ratings 1-5. Not sure if I can do that with checkboxes.

EDIT

Ok so using name="surveyRating[1]" is helping as far as the radio buttons not conflicting on the client side. However, it is not saving correctly the way I have my php set up now. Here is how it is saved currently. What do I need to change to make the [1] work appropriately. Currently it is only saving the last iteration.

$new = array();
$ratings = $_POST['surveyRating'];
$count = count( $ratings );
for ( $i = 0; $i < $count; $i++ ) {
  if ( $ratings[$i] != '' ) {
    $new[$i]['surveyRating'] = stripslashes( strip_tags( $ratings[$i] ) );
  }
}

EDIT 2

So to demonstrate how I accomplished this using the answer below, I had to add [0] as the first iteration in the loop. I was using $items = 0; $items++ to dynamically add a number to each loop.

To make it start at 0, I set $items = -1 that way the first iteration is 0 instead of 1. Hope that makes sense.

Upvotes: 1

Views: 160

Answers (1)

Praveen Kumar Purushothaman
Praveen Kumar Purushothaman

Reputation: 167182

Yep, it does because you have the name with []. That's for array. Remove it and you will get it without array:

<input type="radio" name="surveyRating" value="1" />
<input type="radio" name="surveyRating" value="2" />
<input type="radio" name="surveyRating" value="3" />
<input type="radio" name="surveyRating" value="4" />
<input type="radio" name="surveyRating" value="5" />

For radio buttons with several groups, you have to do something like this:

<!-- Group 1 -->
<input type="radio" name="surveyRating[1]" value="1" />
<input type="radio" name="surveyRating[1]" value="2" />
<input type="radio" name="surveyRating[1]" value="3" />
<input type="radio" name="surveyRating[1]" value="4" />
<input type="radio" name="surveyRating[1]" value="5" />

<!-- Group 2 -->
<input type="radio" name="surveyRating[2]" value="1" />
<input type="radio" name="surveyRating[2]" value="2" />
<input type="radio" name="surveyRating[2]" value="3" />
<input type="radio" name="surveyRating[2]" value="4" />
<input type="radio" name="surveyRating[2]" value="5" />

Upvotes: 1

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