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c#.netjsonjson.net
Ebubekir Çağrı Şen
Ebubekir Çağrı Şen

Reputation: 103

Deserialize json with c# with random root names

I have a json file which has random names in roots but same structure in child elements. I would like to get all the child elements in an array or a list.

Sample json file :

{  
   "-LeHl495vL6vh-8CaLbD":{  
      "apiKey":"sr-tr-137-beea04e44cb452ba0da0ca090b7e61b4ec6ffc69"
   },
   "-LeHl6jrhUEMb7slZcpB":{  
      "apiKey":"sr-tr-137-aef7a23095c0c7baef1ef681bdd8bf9756ac2a17"
   }
}

I have tried these classes but could not do it.

public class RequestedReport
    {
        public Dictionary<string, List<ReportData>> ReportDatas { get; set; }
    }

    public class ReportData
    {
        public string apiKey { get; set; }
    }

So my expected output from deserialization is like List which contains all the apiKeys in json file.

Thanks in advance.

Upvotes: 8

Views: 2082

Answers (1)

Jon Skeet
Jon Skeet

Reputation: 1502206

It looks to me like your JSON represents a Dictionary<string, ReportData> directly. There's no wrapper object, and no lists involved. If you deserialize your JSON to that type, it should be fine. Here's a complete example:

using System;
using System.Collections.Generic;
using System.IO;
using Newtonsoft.Json;

class Program
{
    static void Main()
    {
        var json = File.ReadAllText("test.json");
        var reports = JsonConvert.DeserializeObject<Dictionary<string, ReportData>>(json);

        foreach (var pair in reports)
        {
            Console.WriteLine($"{pair.Key}: {pair.Value.ApiKey}");
        }
    }
}

public class ReportData
{
    [JsonProperty("apiKey")]
    public string ApiKey { get; set; }
}

If you just want the list of API keys, and you don't care about the field names associated with them, you can use:

var apiKeys = reports.Values.Select(x => x.ApiKey).ToList();

Upvotes: 11

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